javascript - 带有模式显示的mysql数据的variabel php

Question

我想在一个页面中使用 modal reveal 创建带有 id 到 div id 的链接

<a href="#?id=<?php echo $id; ?>" class="team-detail" data-reveal-id="single-news"></a>

<!-- Pop Up Windows - Single Blog Post -->
<div id="single-news" class="reveal-modal single-news small" data-reveal>

<?php
     $member = mysql_query("SELECT*FROM team WHERE id = '$_GET[id]'");
     $m = mysql_fetch_array($member);
?>  
<div class="twelve columns first-column">
    <p class="single-news-content"><?php echo $m[quote]; ?></p>
</div>
    <a class="close-reveal-modal">&#215;</a>
</div>

但是 $_GET 不工作，查询不工作

Answer 1

我想你想通过 $id弹出模型中的参数:

试试下面的代码:

<a class="btn btn-primary btn-xs" data-toggle="modal" data-target="#editBox" href="file.php?id=<?php echo $id;?>">

现在创建一个 PHP 文件并将其命名为 file.php

此文件使用模态调用按钮调用 href="file.php?id=<?php echo $id;?"

<?php
//Include database connection here
$Id = $_GET["id"]; //escape the string if you like
// Run the Query
?>
<div class="modal-header">
    <button type="button" class="close" data-dismiss="modal">&times;</button>
    <h4 class="modal-title"><center>Heading</center></h4>
</div>
<?php
     $member = mysql_query("SELECT*FROM team WHERE id = '$_GET[id]'");
     $m = mysql_fetch_array($member);
?>  
<div class="modal-body">
     <p class="single-news-content"><?php echo $m[quote]; ?></p>
</div>
<a class="close-reveal-modal">&#215;</a>
</div>

<script>
$( document ).ready(function() {
    $('#editBox').on('hidden.bs.modal', function () {
          $(this).removeData('bs.modal');
    });
});
</script>

可以看到完整的过程here

希望这有帮助!!!