php - Laravel 5.3 Form Builder 在选择选项上动态分配 'value'

Question

如何在我的 View 中为 Laravel Form Builder Select Options 动态分配“值”？

例子:

函数

public function create()
{
    $categories = \DB::table('categories')->pluck('name', 'id');
    return view('link.create')->with('categories', $categories);
}

查看

<div class="form-group">
    {!! Form::label('Link Category') !!}<br />
    {!! Form::select('category', 
        (['0' => 'Select a Category'] + $categories), 
            null, 
            ['class' => 'form-control']) !!}
</div>

结果

<select name="category" class="form-control">
    <option value="0">Select a Category</option>
    <option value="1">Laravel</option>
    <option value="2">Zend Framework</option>
    <option value="3">CakePHP</option>
    <option value="4">PHP</option>
</select>

我希望选择选项的“值”与选项内容相同。

喜欢:

    <option value="1">Laravel</option>

应该是这样的:

    <option value="Laravel">Laravel</option>

Answer 1

如果你只提取name，你可以这样做:

public function create()
{
    $categories = \DB::table('categories')->pluck('name');
    // creates ['Laravel' => 'Laravel', 'PHP' => 'PHP'...]
    $categories = array_combine($categories, $categories);
    return view('link.create')->with('categories', $categories);
}