c++ - 移动数组中字符串的位置

Question

int moveToEnd(string a[], int n, int pos);

Eliminate the item at position pos by copying all elements after it one place to the left. Put the item that was thus eliminated into the last position of the array. Return the original position of the item that was moved to the end. Here's an example:

string actors[5] = { "peter", "lois", "meg", "chris", "stewie" };
int j = moveToEnd(actors, 5, 1);  // returns 1
// actors now contains:  "peter"  "meg"  "chris"  "stewie"  "lois"

这是我目前所拥有的:

int moveToEnd(string a[], int n, int pos)
{int i = 0;
int initial;
int initial2;
int initial3;
for (i=0; i<n; i++)
    {if (i<pos)
        initial=i-1;
    if (i>pos)
        initial2=i-1;
    else 
        pos + (n-pos);
}}

这是完全错误的，但我一直在试图弄清楚如何将位置移到最后，而不是将所有其他元素移到左边。

Answer 1

string save = arr[pos];

for (int i = pos; i < n - 1; i++)
   arr[i] = arr[i + 1];

arr[n - 1] = save;