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javascript - 单个页面中的两个表单,并使用 Codeigniter 使用 Bootstrap 模式

转载 作者:行者123 更新时间:2023-11-28 03:46:27 24 4
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$('#form1').on('click',function(e){
e.preventDefault();
$('#emailModal').modal("show"); // open the modal
});

$(document).on('click','#sendEmail',function(){
$('#UpdateEmailModal').modal("show"); // open the modal
}
});
$(document).on('click','#UpdateSendEmail',function(){
$('#form1method').submit();
});

$(document).on('click','#Update_Close',function(){
$('#form2method').submit();
});

$(document).on('click','#Close',function(){
window.location = "<?php echo base_url(); ?>controller/page_method";
});
<!--Form 1-->

<form action="<?php echo base_url(); ?>mycontroller/method1" method="post" id="form1method">
<input type="text" name="name">
<input type="email" name="email">
<button type="submit" id="form1">Submit</button>
</form>

<!--Form 2 -->
<form action="<?php echo base_url(); ?>mycontroller/method2" method="post" id="form2method">
<input type="text" name="name">
<input type="email" name="email">
<button type="submit" id="form2">Submit</form>
</form>

<!--Modal 1 -->
<!--Email Modal -->
<div id="emailModal" class="modal fade" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">&times;</button>
<h4 class="modal-title">Send Email to User</h4>
</div>
<div class="modal-body">
<label class="col-md-3">To Email</label>
<div class="form-group col-md-9">
<input type="email" class="form-control" name="email_id" id="email_id" placeholder="Email ID">
</div>
<label class="col-md-3">Message</label>
<div class="form-group col-md-9">
<textarea name="message" id="message" class="form-control" placeholder="Message"></textarea>
</div>
</div>
<div class="modal-footer">
<button type="submit" class="btn btn-info btn-block" id="sendEmail"><strong>Update</strong></button>
<button class="btn btn-danger pull-right btn-block" data-dismiss="modal" id="Close"><strong>Close</strong></button>
</div>
</div>
</div>
</div>

<!--Modal 2 -->
<!--Email Status and Update Modal -->
<div id="UpdateEmailModal" class="modal fade" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">&times;</button>
<h4 class="modal-title">Update Form</h4>
</div>
<div class="modal-body">
<p>Click Submit to Update and Send Email (or) Click Cancel to Update</p>
</div>
<div class="modal-footer">
<button type="submit" class="btn btn-info btn-block" id="UpdateSendEmail"><strong>Submit</strong></button>
<button class="btn btn-danger pull-right btn-block" data-dismiss="modal" id="Update_Close"><strong>cancel</strong></button>
</div>
</div>
</div>
</div>

enter code here
<?php
*//My Controller*
public function method1(){
$result = $this->model->update_model();
if($result == true){
$this->session->set_flashdata("msg","post_page");
redirect("post_page");
}}
public function method2(){
$result = $this->model->update_model2();
if($result == true){
$this->session->set_flashdata("msg","post_page");
redirect("post_page");
}}

*`//My Model`*
public function update_model(){
$data = array(
'name' => $this->input->post("name"),
'email' => $this->input->post("email")
);
$this->db->update('user',$data);
}

public function update_model2(){
$data = array(
'name' => $this->input->post("name"),
'email' => $this->input->post("email"),
'status' => "1"
);
$this->db->update('user',$data);
}
?>

当单击编辑表单时,将打开编辑页面,因为我有两个表单(Form1 和 Form2)。一页中只能出现一个表单。当我单击 Form1 的提交时,将打开 Modal1,单击“更新”按钮时,将打开 Modal2。基于 Modal2 中的两个按钮(提交和取消),应该会发生响应。就像如果我单击 Controller 中的“提交”方法2 应该执行,否则如果我单击方法1 应该执行。在 Controller 中如何做到这一点?我不知道我这样做是否正确。如果你们有任何想法可以解决这个问题,请帮助我。

提前致谢

最佳答案

您可以为每个提交按钮指定不同的名称。因此,当您按下提交按钮时,就像在 form1 中一样,form1submit_btn ,页面重新加载并简单地检查帖子输入:

您按钮

<button type="submit" name="form1submit_btn" class="btn btn-info btn-block" id="sendEmail"><strong>Update</strong></button>

您的两个表单操作具有相同的操作 action="<?base_url("myController/method")?> ,然后直接在 Controller 中处理它们:

function method(){
//form 1 has been submit
if($this->input->post("form1submit_btn")){

$result = $this->model->update_model();
if($result == true)
$this->session->set_flashdata("msg","post_page");

}

//form 2 has been submit
if($this->input->post("form2submit_btn")){

$result = $this->model->update_model2();
if($result == true)
$this->session->set_flashdata("msg","post_page");

}

redirect("post_page");

}

关于javascript - 单个页面中的两个表单,并使用 Codeigniter 使用 Bootstrap 模式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48437293/

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