javascript - 如何将图像显示到弹出窗口

Question

我已经使用 readAsdataUrl 读取了内存中的图像javascript函数。现在我需要在一个弹出窗口中显示此图像，该窗口在单击现有页面中的按钮时打开。

我该怎么做？有什么方法可以从内存中读取图像，然后将其显示在新的弹出窗口中？

Answer 1

检查这个 - http://www.html5rocks.com/en/tutorials/file/dndfiles/#toc-reading-files

似乎它有你需要的例子:

<style>
  .thumb {
    height: 75px;
    border: 1px solid #000;
    margin: 10px 5px 0 0;
  }
</style>

<input type="file" id="files" name="files[]" multiple />
<output id="list"></output>

<script>
  function handleFileSelect(evt) {
    var files = evt.target.files; // FileList object

    // Loop through the FileList and render image files as thumbnails.
    for (var i = 0, f; f = files[i]; i++) {

      // Only process image files.
      if (!f.type.match('image.*')) {
        continue;
      }

      var reader = new FileReader();

      // Closure to capture the file information.
      reader.onload = (function(theFile) {
        return function(e) {
          // Render thumbnail.
          var span = document.createElement('span');
          span.innerHTML = ['<img class="thumb" src="', e.target.result,
                            '" title="', escape(theFile.name), '"/>'].join('');
          document.getElementById('list').insertBefore(span, null);
        };
      })(f);

      // Read in the image file as a data URL.
      reader.readAsDataURL(f);
    }
  }

  document.getElementById('files').addEventListener('change', handleFileSelect, false);
</script>

只需将那个 div 替换为您想要的弹出窗口即可