javascript - 在数据库中创建新位置后，直接重定向到新创建的 View

Question

在我的网站上您可以创建协作者。我有一个带有表格的 Blade View ，您可以在其中看到所有内容。我希望在创建新协作者后返回新创建协作者的主视图。

我想我可以将它添加到我的javascript函数中，或者可能添加到路由函数中，而不是像return view('person.profile.profile-view')那样使用返回 ; 但我不知道如何从新创建的字段传递我需要的所有数据。

此外，我的协作者 View 需要大量数据，这是它的 Controller :

 public function profileView($id)
    {
        $person = $this->personRepository->getByIdWith($id, ['person_title', 'country', 'salutation']);
        $practitioner_id = $this->practitionerRepository->getIdByPersonId($id);
        $practitioner = $this->practitionerRepository->getById($practitioner_id);
        $specialty_id = PractitionerSpecialty::where('practitioner_id', $practitioner_id)->value('specialty_id');

        return view('person.profile.profile-view')
            ->with('person', $person)
            ->with('id', $id)
            ->with('person_titles', $this->personTitleRepository->getAll())
            ->with('countries', Country::all())
            ->with('specialties', Specialty::all())
            ->with('specialty', Specialty::where('specialty_id', $specialty_id)->value('name'))
            ->with('competence_levels', CompetenceLevel::all())
            ->with('salutations', PersonSalutation::all())
            ->with('practitioner', $practitioner)
            ->with('practitioner_specialty', PractitionerSpecialty::where('practitioner_id', $practitioner_id)->first())
            ->with('practitioner_competence_level', PractitionerCompetenceLevel::where('practitioner_id', $practitioner_id)->first());
    }

我的 php 创建表单

<div class="modal fade crud-modal" id="create-Modal" tabindex="-1" role="dialog" style="z-index: 1050; display: none;"
     aria-hidden="true">

               [...]                     

            <div class="modal-footer">
                <button type="button" class="btn btn-default btn-round waves-effect "
                        data-dismiss="modal">{{trans('buttons.close')}}</button>
                <button type="button" id="create_final_btn" class="btn btn-success btn-round"
                        >{{trans('buttons.add')}}</button>
            </div>
        </div>
    </div>
</div>

var create = (function(){
    var onSuccess;
    var onHashSuccess;

    var createButton = function(fieldValues, createUrl, required) {
        $("#create_final_btn").click(function () {
            forms.postObject(forms.readForm(fieldValues, '_create', undefined,  required), createUrl, onSuccess);
        });
    };

    [...]

    var setOnSuccess = function(fun) {
      onSuccess = fun;
    };
    var setOnHashSuccess = function(fun) {
        onHashSuccess = fun;
      };

    return {
        createButton: createButton,
        createHashItemButton: createHashItemButton,
        openCreateDialogButton: openCreateDialogButton,
        setOnSuccess: setOnSuccess,
        setOnHashSuccess: setOnHashSuccess,
        openCreateTrainingPlanButton: openCreateTrainingPlanButton
    };
}());

我在 route 的功能:

public function addPerson(Request $request) {
        $this->validate($request, [
                'data' => 'required',
                'data.first_name' => 'required',
                'data.last_name' => 'required',
                'data.active' => 'required',
                'data.person_salutation_id' => 'required',

            ]
        );
        $this->repository->create($request->all()['data']);
        return back();
    }

我认为最好的方法是在 javascript 函数中做到这一点。如果有人可以引导我找到最佳解决方案，那就太好了。

Answer 1

相反:

return back();

使用

$object = $this->repository->create($request->all()['data']);

return redirect()->route('routename', ['id' => $object->id]);