gpt4 book ai didi

html - 在家谱中的单个节点上结束两个节点

转载 作者:行者123 更新时间:2023-11-28 03:32:55 26 4
gpt4 key购买 nike

我想在这个 fiddle 中的一个节点上结束两个节点 http://jsfiddle.net/uPdZX

HTML代码:

<!--
We will create a family tree using just CSS(3)
The markup will be simple nested lists
-->
<div class="tree">
<ul>
<li>
<a href="#">Parent</a>
<ul>
<li>
<a href="#">Child</a>
<ul>
<li>
<a href="#">Grand Child</a>
</li>
</ul>
</li>
<li>
<a href="#">Child</a>
<ul>
<li><a href="#">Grand Child</a></li>
<li>
<a href="#">Grand Child</a>
<ul>
<li>
<a href="#">Great Grand Child</a>
</li>
<li>
<a href="#">Great Grand Child</a>
</li>
<li>
<a href="#">Great Grand Child</a>
</li>
</ul>
</li>
<li><a href="#">Grand Child</a></li>
</ul>
</li>
</ul>
</li>
</ul>
</div>

CSS:

/*Now the CSS*/
* {margin: 0; padding: 0;}

.tree ul {
padding-top: 20px; position: relative;

transition: all 0.5s;
-webkit-transition: all 0.5s;
-moz-transition: all 0.5s;
}

.tree li {
float: left; text-align: center;
list-style-type: none;
position: relative;
padding: 20px 5px 0 5px;

transition: all 0.5s;
-webkit-transition: all 0.5s;
-moz-transition: all 0.5s;
}

/*We will use ::before and ::after to draw the connectors*/

.tree li::before, .tree li::after{
content: '';
position: absolute; top: 0; right: 50%;
border-top: 1px solid #ccc;
width: 50%; height: 20px;
}
.tree li::after{
right: auto; left: 50%;
border-left: 1px solid #ccc;
}

/*We need to remove left-right connectors from elements without
any siblings*/
.tree li:only-child::after, .tree li:only-child::before {
display: none;
}

/*Remove space from the top of single children*/
.tree li:only-child{ padding-top: 0;}

/*Remove left connector from first child and
right connector from last child*/
.tree li:first-child::before, .tree li:last-child::after{
border: 0 none;
}
/*Adding back the vertical connector to the last nodes*/
.tree li:last-child::before{
border-right: 1px solid #ccc;
border-radius: 0 5px 0 0;
-webkit-border-radius: 0 5px 0 0;
-moz-border-radius: 0 5px 0 0;
}
.tree li:first-child::after{
border-radius: 5px 0 0 0;
-webkit-border-radius: 5px 0 0 0;
-moz-border-radius: 5px 0 0 0;
}

/*Time to add downward connectors from parents*/
.tree ul ul::before{
content: '';
position: absolute; top: 0; left: 50%;
border-left: 1px solid #ccc;
width: 0; height: 20px;
}

.tree li a{
border: 1px solid #ccc;
padding: 5px 10px;
text-decoration: none;
color: #666;
font-family: arial, verdana, tahoma;
font-size: 11px;
display: inline-block;

border-radius: 5px;
-webkit-border-radius: 5px;
-moz-border-radius: 5px;

transition: all 0.5s;
-webkit-transition: all 0.5s;
-moz-transition: all 0.5s;
}

/*Time for some hover effects*/
/*We will apply the hover effect the the lineage of the element also*/
.tree li a:hover, .tree li a:hover+ul li a {
background: #c8e4f8; color: #000; border: 1px solid #94a0b4;
}
/*Connector styles on hover*/
.tree li a:hover+ul li::after,
.tree li a:hover+ul li::before,
.tree li a:hover+ul::before,
.tree li a:hover+ul ul::before{
border-color: #94a0b4;
}

这是代码......我想做的是结束一个孙子的孙子......如何实现这一点......我应该做什么......任何帮助将不胜感激: )

最佳答案

如果您删除以下 CSS3 语句(或将内边距设置为 20px),它们将处于同一级别:

/*Remove space from the top of single children*/
.tree li:only-child{ padding-top: 0;}

不过,您仍需要添加一个额外的垂直连接器(如果需要)。

关于html - 在家谱中的单个节点上结束两个节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16466277/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com