带有结构的 C++ getline()

Question

struct car
{
  string name;
  int year;
};    

int main() {
    int noOfCars;
    cout<<"enter no_ of cars : ";    
    cin>>noOfCars;    
    car* cars = new car[noOfCars];    
    for(int i=0;i<noOfCars;i++)
    {
        cout<<"Car #"<<i<<endl;
        cout<<"Name : ";    
        getline(cin,(cars[i].name));  //here is the problem 
        cout<<"\n year : ";    
        cin>>cars[i].year;    
        cout<<endl;
    }
}

将整行作为字符串输入到 strcut 中的名称时出现问题，甚至不接受任何内容并直接继续获取年份 ... :S ???

它适用于 cin，但我想要整行!它适用于全局定义的字符串，但不适用于结构中的 this

Answer 1

在 getline 之后插入 cin.ignore( 1000, '\n' );。

#include<string>
#include<iostream>
using namespace std;

struct car
{
  string name;
  int year;
};    

int main() {
    int noOfCars;
    cout<<"enter no_ of cars : ";    
    cin>>noOfCars;    
    car* cars = new car[noOfCars];    
    for(int i=0;i<noOfCars;i++)
    {
        cin.clear();


        cout<<"Car #"<<i<<endl;
        cout<<"Name : ";    
        getline(cin,(cars[i].name));  //here is the problem 

     cin.ignore( 1000, '\n' );

        cout<<"\n year : ";    
        cin>>cars[i].year;    
        cout<<endl;

    }
    return 0;
}