c++ - 将结构传递给 Visual Studio 中的函数

Question

我在做一个项目，我试图将一个结构传递给一个函数，我尝试了各种方法，但我仍然做不到。我收到错误消息:

illegal use of this type of expression.

非常感谢您的帮助。

    #include <stdio.h>
    #include <stdlib.h>
    #include <time.h>

 struct big{
        int day;
        int year;
        char month[10];
        } ;

      void gen(struct big);
      void main()
    {
int choice;

printf("\t\t\t\t\t*MENU*\n\n\n");
printf("\t\tGenerate Buying/Selling Price-------------------PRESS 1\n\n");
printf("\t\tDisplay Foreign Exchange Summary----------------PRESS 2\n\n");
printf("\t\tBuy Foreign Exchange----------------------------PRESS 3\n\n");
printf("\t\tSell Foreign Exchange---------------------------PRESS 4\n\n");
printf("\t\tExit--------------------------------------------PRESS 5\n\n\n\n");
printf("\t\tPlease enter your choice");
scanf("%d", &choice);

if (choice == 1)
{
    gen(big);
}
system("pause");

    }

void gen(big rec)
{
printf("Enter the date in the format: 01-Jan-1993");
scanf("%d %s %d", &rec.day, &rec.month, &rec.year);
}

Answer 1

您正在尝试传递结构定义本身，创建它的一个实例然后传递它。

big myBig;
gen(myBig);