javascript - 减少函数插入数组值

Question

我有对象数组:

const items = [{ search_type: 'environment',
    search_code: 'TBA_ENVIRONMENT00002',
    asset_code: 'ASSET00002' },
  { search_type: 'job',
    search_code: 'TBA_JOB00002',
    asset_code: 'ASSET00002' },
  { search_type: 'environment',
    search_code: 'TBA_ENVIRONMENT00002',
    asset_code: 'ASSET00004' },
  { search_type: 'job',
    search_code: 'TBA_JOB00002',
    asset_code: 'ASSET00004' },
  { search_type: 'job',
    search_code: 'TBA_JOB00003',
    asset_code: 'ASSET00004' },
  { search_type: 'scene',
    search_code: 'TBA_SCENE00006',
    asset_code: 'ASSET00002' },
 ];

并且想要返回类似的内容:

{
ASSET00002: {
   environment:["TBA_ENVIRONMENT00002"],
   job:["TBA_JOB00002"],
   scene:["TBA_SCENE00006"]
},
ASSET00004: {
   environment:["TBA_ENVIRONMENT00002"],
   job:["TBA_JOB00002","TBA_JOB00003"]
},
}

这里我使用Reduce函数来使用这个逻辑:

const result = items.reduce((acc, item) => {
  const { search_type, search_code, asset_code } = item;
  return {
    ...acc,
    [asset_code]: {
      ...acc[asset_code], [search_type]: [search_code]
    },
  };
}, {});

我得到以下结果:

{
ASSET00002: {
   environment:["TBA_ENVIRONMENT00002"],
   job:["TBA_JOB00002"],
   scene:["TBA_SCENE00006"]
},
ASSET00004: {
   environment:["TBA_ENVIRONMENT00002"],
   job:["TBA_JOB00003"]
},
}

在返回“ASSET00004”->“job”时，我应该得到具有两个值的数组，但只得到一个。我知道我的代码缺少一些内容，但无法找到将值正确插入数组的方法。如有任何帮助，我们将提前感激不尽。

Answer 1

您可以通过单个 reduce 方法来完成此操作，确保在迭代对象时添加到任何现有数组:

const items = [{ search_type: 'environment',
    search_code: 'TBA_ENVIRONMENT00002',
    asset_code: 'ASSET00002' },
  { search_type: 'job',
    search_code: 'TBA_JOB00002',
    asset_code: 'ASSET00002' },
  { search_type: 'environment',
    search_code: 'TBA_ENVIRONMENT00002',
    asset_code: 'ASSET00004' },
  { search_type: 'job',
    search_code: 'TBA_JOB00002',
    asset_code: 'ASSET00004' },
  { search_type: 'job',
    search_code: 'TBA_JOB00003',
    asset_code: 'ASSET00004' },
  { search_type: 'scene',
    search_code: 'TBA_SCENE00006',
    asset_code: 'ASSET00002' },
 ];

const assets = items.reduce((acc, el) => {
  if (!acc[el.asset_code]) {
    acc[el.asset_code] = {};
  }
  acc[el.asset_code][el.search_type] = 
    [...acc[el.asset_code][el.search_type] || [], el.search_code];
  return acc;
}, {});

console.log(assets);