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c++ - 错误 : expected unqualified-id while using boost mutex

转载 作者:行者123 更新时间:2023-11-28 03:07:47 27 4
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我尝试实现一个基于boost mutex的锁宏,代码如下:

#include <boost/thread.hpp>
#include <iostream>

using namespace std;

#define lock(x) if(Lock _lock_=x){}else

class Mutex{
public:
friend class Lock;

private:
boost::mutex mutex_;

void Lock(){
mutex_.lock();
};

void Unlock(){
mutex_.unlock();
};
};

class Lock{
public:
Lock(Mutex& mutex):mutex_(mutex){mutex_.Lock();};
~Lock(){mutex_.Unlock();};

operator bool() const {
return false;
}

private:
Mutex& mutex_;
};

void wait(int seconds)
{
boost::this_thread::sleep(boost::posix_time::seconds(seconds));
}

void thread()
{
Mutex mtx;
for (int i = 0; i < 5; ++i)
{
lock(mtx){
wait(1);
std::cout << "Thread " << boost::this_thread::get_id() << ": " << i << std::endl;
}
}
}

int main()
{
boost::thread t1(thread);
boost::thread t2(thread);
t1.join();
t2.join();
}

当我在 Mac 操作系统中使用 clang++ -std=c++11 -stdlib=libc++ lock_raii.cc -lboost_system -lboost_thread 编译它时。出现错误信息:

lock_raii.cc:16:10: error: expected unqualified-id
mutex_.lock();
^
lock_raii.cc:6:17: note: expanded from macro 'lock'
#define lock(x) if(Lock _lock_=x){}else
^
1 error generated.

那么,它有什么问题呢?

最佳答案

这是 mutex_.lock(); 在宏扩展后的样子:

mutex_.if(Lock _lock_=){}else;

关于c++ - 错误 : expected unqualified-id while using boost mutex,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19282035/

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