C++ 继承 : Calling constructor w/args

Question

我试图在子类的带参数的构造函数中调用带参数的父类的构造函数，但我收到编译器错误“expected primary expression before ...”。这是我的:

class Ship {
    private:
        string shipName;
        int yearBuilt;
    public:
        Ship();
        Ship(string name, int year);
};
class CruiseShip: public Ship {
    private:
        int maxPeople;
    public:
        CruiseShip()
        : Ship() {
            maxPeople = 100;
        }
        CruiseShip(int m)
        : Ship(string name, int year) {
            maxPeople = m;
        }
};
Ship::Ship() {
    shipName = "Generic";
    yearBuilt = 1900;
}
Ship::Ship(string name, int year) {
    shipName = name;
    yearBuilt = year;
}

这是我遇到问题的特定代码:

    CruiseShip(int m)
    : Ship(string name, int year) {
        maxPeople = m;
    }

我的目标是能够创建一个对象，CruiseShip c1，它有 3 个参数来设置名称、年份和最大人数。我一直在网上阅读，它告诉我这应该没问题，但我显然做错了什么。如果有任何意见，我将不胜感激!

Answer 1

您需要像这样将参数传递给父类构造函数:

CruiseShip(int m, string name, int year): Ship(name, year), maxPeople(m) {}

更好的是，你应该在初始化列表中将 maxPeople 设置为 m。