javascript - 从 json 字符串转换为 json 对象后如何从 Typescript 中的对象数组获取结果，我的编码有什么问题

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请参阅下面我的编码。从 json 字符串转换为 json 对象后，我正在从对象数组中简单提取数据。

export class FourColumnResults {

    constructor(private column1: string, private column2: string,
        private column3: string, private column4: string) {

    }

    public get $column1(): string {
        return this.column1;
    }

    public set $column1(value: string) {
        this.column1 = value;
    }


    /** all getter and setter methods */
}


export class ValidationSummary {

    constructor(private column1: string, private column2: string, private column3: string,
        private column4: string, private column5: string, private column6: string,
        private column7: string) {

    }

    public get $column1(): string {
        return this.column1;
    }

    public set $column1(value: string) {
        this.column1 = value;
    }

    /** all getter and setter methods */

}

从“./FourColumnResult”导入{ FourColumnResults }；从 './ValidationSummary' 导入 { ValidationSummary };

export class MyConverter {

    public convert(jsonString: string): FourColumnResults[] {
        const results: FourColumnResults[] = [];
        const valSummary: ValidationSummary[] = JSON.parse(jsonString);
        console.log("ValSummary object======== ", valSummary); // This is printing correctly

        for(let i = 0; i < valSummary.length; i++) {
            const value: ValidationSummary = valSummary[i];
            console.log("=====>"+value.$column1);
        }

        return results;
    }

}

以下是我从系统获取的实际 json 字符串。

[
  {
    "column1": "Data-1",
    "column2": "Data-2",
    "column3": "Data-3",
    "column4": "Data-4",
    "column5": "Data-5",
    "column6": "Data-6",
    "column7": "Data-7"
  },
  {
    "column1": "Data-11",
    "column2": "Data-12",
    "column3": "Data-13",
    "column4": "Data-14",
    "column5": "Data-15",
    "column6": "Data-16",
    "column7": "Data-17"
  },
  {
    "column1": "Data-31",
    "column2": "Data-32",
    "column3": "Data-33",
    "column4": "Data-34",
    "column5": "Data-35",
    "column6": "Data-36",
    "column7": "Data-37"
  }
]

这里的问题是，我能够将上面的 json 字符串解析为我类型的 json 对象 ValidationSummary.ts使用以下编码。

const valSummary: ValidationSummary[] = JSON.parse(jsonString);

但是，我无法从以下编码中获得结果。

for(let i = 0; i < valSummary.length; i++) {
            const value: ValidationSummary = valSummary[i];
            console.log("=====>"+value.$column1); // Prints Undefined
        }

我的编码有什么问题吗？请帮我解决。

Answer 1

应该是value.column1而不是value.$column1

for(let i = 0; i < valSummary.length; i++) {
    const value: ValidationSummary = valSummary[i];
    console.log("=====>"+value.column1); // Prints the value
}