- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我从命令行参数中读入,它们如下:
0.5 3 10 50
maxClock 是最后一个参数,在本例中为 50。然后我有一个这样的 for 循环:
for(int k = 1; k < maxClock; k++)
{
<code>
}
但是无论出于何种原因,我的程序都不会计数到 k。有时它只会数到 9,然后是 34,然后是 14,等等......我不知道发生了什么。有人可以给我另一种观点吗?
代码如下:
/* * 驱动.cpp
*
* This program simulates a bank with customers walking in for service and seeing tellers.
* This program implements a classic Queue style system.
*
* Disclaimer:
*
* - For some reason, the program will not run up until the time maxClock given in the command line arguments.
* This prevents the program from being able to print out the averageQueue length, maxQueueLength, etc at the
* bottom right after the for-loop.
*
*
*
*/
////////////////////////////////////////////////////////////////////
///Includes///
////////////////////////////////////////////////////////////////////
#include <iostream>
#include <vector>
#include <cstdlib>
#include "Queue.h"
#include "Customer.h"
#include "QueueNode.h"
#include "Teller.h"
using namespace std;
int main(int argc, char *argv[])
{
srand(time(NULL)); //seeds the random time generator
if(argc != 5)
{
cout << "You must enter at least 5 command line arguments " << endl;
exit(1);
}
/******************Command Line Args-Variables***************************/
double p = atof(argv[1]);
int numTellers = atoi(argv[2]); //number of the tellers (M)
int maxService = atoi(argv[3]);
int maxClock = atoi(argv[4]); //simulation time (N)
/******************Local Variables***************************/
int numberOfCustomers = 0;
int serv;
int randProb;
int totalWait;
unsigned long long AverageWaitTime;
int customerWillBeFinished;
int maxQLength;
int counter;
int AverageQueueLength;
int wait;
int individualWaitTime;
int OtherThanK;
int a = 10000;
//Displays to user to double checks to make sure you entered in the arguments correctly
cout << "------------------------------------------------------------" << endl;
cout << "These are the arguments that you gave the program: " << endl;
cout << endl;
cout << "The p value is: " << p << endl;
cout << "The number of tellers: " << numTellers << endl;
cout << "The max service time is: " << maxService << endl;
cout << "The max clock is: " << maxClock << endl;
cout << endl;
cout << "------------------------------------------------------------" << endl;
cout << "\n";
/******************Declaration of Queue & Vector***************************/
Queue<Customer> line;
vector<Teller> teller(numTellers);
//loop to go through entire clock until the maxClock is reached
for(int k = 1; k < maxClock; k++)
{
OtherThanK = k;
randProb = ((rand() % 100) + 1); //generates a random number seeded with system time
if(randProb < p*100)
{
serv = ((rand() % maxService) + 1); //generates a random number seeded with system time
Customer customer(OtherThanK, serv); //passes in current time and service time (randomizeD)
line.enqueue(customer); //pushes a customer onto the Queue.
cout << "Customer arriving in queue at time: " << OtherThanK << endl;
}
customerWillBeFinished = serv + OtherThanK + 1;
for(int i = 0; i < numTellers; i++)
{
if(teller[i].isFree() && (!line.isempty())) //checks to see if a teller is empty
{
cout << "Teller " << i << " is now free." << endl;
Customer frontCustomer; //declares a customer called frontCustomer. This is the customer who is at the front of the Queue.
line.dequeue(frontCustomer); //pulls off a customer from the Queue.
wait = OtherThanK - frontCustomer.getArrivalTime();
numberOfCustomers++; //increases by 1 each time through to keep tracking of the # of Customers.
totalWait = totalWait + wait;
cout << "Customer going to teller " << i << " at time " << frontCustomer.getArrivalTime() << endl; //retrieves arrival time
cout << "This customer had to wait in line for " << wait << " minutes." << endl; //labs() is a function used to determine absolute value
cout << "This customer will require " << serv << " minutes of service" << endl;
teller[i].addCustomer(frontCustomer);
line.remove(frontCustomer); //once cycled through, removes the customer from the Queue.
}
}
cout << endl;
cout << "Time is: "<< k << endl;
cout << " \n Number of customers: " << numberOfCustomers << " " << "Total wait so far: " << std::labs(totalWait) << endl; //labs() is a function used to determine absolute value
}
///////// WON'T PRINT ANY OF THIS OUT BECAUSE IT WONT EXIT LOOP ///////
cout << "test" <<endl;
AverageWaitTime = totalWait/numberOfCustomers;
cout << "Average wait time is: " << AverageWaitTime*a << endl;
maxQLength = line.getLength();
cout << "The max Queue length is " << maxQLength << endl;
AverageQueueLength = maxQLength/OtherThanK;
cout << "The Average Queue Length is " << AverageQueueLength;
}
输出示例:(每次都变,这次统计到20):
------------------------------------------------------------
These are the arguments that you gave the program:
The p value is: 0.5
The number of tellers: 3
The max service time is: 10
The max clock is: 50
------------------------------------------------------------
Max Clock is 50
Time is: 0
Number of customers: 0 Total wait so far: 0
Max Clock is 50
Time is: 1
Number of customers: 0 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 2
Teller 0 is now free.
Customer going to teller 0 at time 2
This customer had to wait in line for 0 minutes.
This customer will require 4 minutes of service
Time is: 2
Number of customers: 1 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 3
Teller 1 is now free.
Customer going to teller 1 at time 3
This customer had to wait in line for 0 minutes.
This customer will require 10 minutes of service
Time is: 3
Number of customers: 2 Total wait so far: 0
Max Clock is 50
Time is: 4
Number of customers: 2 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 5
Teller 2 is now free.
Customer going to teller 2 at time 5
This customer had to wait in line for 0 minutes.
This customer will require 7 minutes of service
Time is: 5
Number of customers: 3 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 6
Teller 0 is now free.
Customer going to teller 0 at time 6
This customer had to wait in line for 0 minutes.
This customer will require 2 minutes of service
Time is: 6
Number of customers: 4 Total wait so far: 0
Max Clock is 50
Time is: 7
Number of customers: 4 Total wait so far: 0
Max Clock is 50
Time is: 8
Number of customers: 4 Total wait so far: 0
Max Clock is 50
Time is: 9
Number of customers: 4 Total wait so far: 0
Max Clock is 50
Time is: 10
Number of customers: 4 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 11
Teller 0 is now free.
Customer going to teller 0 at time 11
This customer had to wait in line for 0 minutes.
This customer will require 8 minutes of service
Time is: 11
Number of customers: 5 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 12
Teller 2 is now free.
Customer going to teller 2 at time 12
This customer had to wait in line for 0 minutes.
This customer will require 5 minutes of service
Time is: 12
Number of customers: 6 Total wait so far: 0
Max Clock is 50
Time is: 13
Number of customers: 6 Total wait so far: 0
Max Clock is 50
Time is: 14
Number of customers: 6 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 15
Teller 1 is now free.
Customer going to teller 1 at time 15
This customer had to wait in line for 0 minutes.
This customer will require 10 minutes of service
Time is: 15
Number of customers: 7 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 16
Time is: 16
Number of customers: 7 Total wait so far: 0
Max Clock is 50
Customer arriving in queue at time: 17
Teller 2 is now free.
Customer going to teller 2 at time 16
This customer had to wait in line for 1 minutes.
This customer will require 2 minutes of service
Time is: 17
Number of customers: 8 Total wait so far: 1
Max Clock is 50
Time is: 18
Number of customers: 8 Total wait so far: 1
Max Clock is 50
Time is: 19
Number of customers: 8 Total wait so far: 1
Max Clock is 50
Time is: 20
Number of customers: 8 Total wait so far: 1
Max Clock is 50
Customer arriving in queue at time: 21
Teller 0 is now free.
Customer going to teller 0 at time 21
This customer had to wait in line for 0 minutes.
This customer will require 10 minutes of service
Customer.h 类:
/*
* Customer.h
*
*/
#ifndef CUSTOMER_H_
#define CUSTOMER_H_
#include <iostream>
#include "QueueNode.h"
#include "Queue.h"
#include "Teller.h"
#include <cstdlib>
using namespace std;
class Customer
{
public:
int serviceTime;
int arrivalTime;
Customer()
{
serviceTime = 0;
arrivalTime = 0;
}
Customer(int arrival, int maxService)
{
arrivalTime = arrival;
serviceTime = maxService;
}
int getServiceTime()
{
return serviceTime;
}
bool isDone()
{
serviceTime--;
return serviceTime <= 0;
}
int getArrivalTime()
{
return arrivalTime;
}
void MinutePasses()
{
serviceTime--;
}
};
#endif /* CUSTOMER_H_ */
Teller.h 类:
/*
*
*/
#ifndef TELLER_H_
#define TELLER_H_
#include <iostream>
#include "Customer.h"
#include "QueueNode.h"
#include "Queue.h"
using namespace std;
class Teller
{
private:
//bool isOccupied;
Customer customer;
protected:
bool free;
public:
Teller()
{
//isOccupied = false;
free = true;
}
bool isFree()
{
//return free; - > B C
if(!free)
{
customer.serviceTime--;
if(customer.serviceTime == 0)
{
free = true;
return true;
}
else return false;
}
{
return true;
}
}
void addCustomer(Customer C)
{
customer = C;
free = false;
}
void CustMinutePasses()
{
if(!free)
{
customer.MinutePasses();
}
}
Customer & getCustomer()
{
return customer;
}
void setAvailability(bool b)
{
free = b;
}
/*
void setAvailability(bool b)
{
free = b;
}
*/
};
#endif /* TELLER_H_ */
最佳答案
程序确实应该运行到 maxclock-1 (!),除非它因为错误而崩溃(或挂起)。循环中没有其他条件,您似乎没有更改循环索引或边界。
当我使用我在 http://www.cplusplus.com/forum/general/71229/ 中找到的经过调整的队列实现来运行它时,它似乎可以正常工作。 .
由于您不提供队列实现,因此队列可能是错误的来源。
一个可能的原因:我注意到您然后移除 frontCustomer。作为出列的一部分,“我的”队列实现从队列中删除了第一个元素。我使用的原始队列实现没有提供 remove();由于您的方法需要一个参数,因此我假设它将使用默认的运算符==()在整个队列中搜索该特定元素。我不知道当该元素不存在时您的队列会做什么,尤其是当队列为空时。
@Damien Black:完全错了。请修复您的评论。你会因为它而在 comp.lang.c++ 上被贬低,cf。 https://groups.google.com/d/msg/comp.lang.c++/3d9ts9JuA-Q/6PtGSoXSIHQJ
C++ 按值传递,除非形式参数在函数签名中通过前缀 & 符号指定为引用。您可能会将语义与 C# 混淆。
虽然 C# 通过引用处理类,但这些引用是按值 (!) 传递的,除非您限定形参和实参“ref”。
关于c++ - 有人能告诉我为什么我的 for() 循环不会一直计数吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21924885/
我是 PHP 新手。我一直在脚本中使用 for 循环、while 循环、foreach 循环。我想知道 哪个性能更好? 选择循环的标准是什么? 当我们在另一个循环中循环时应该使用哪个? 我一直想知道要
我在高中的编程课上,我的作业是制作一个基本的小计和顶级计算器,但我在一家餐馆工作,所以制作一个只能让你在一种食物中读到。因此,我尝试让它能够接收多种食品并将它们添加到一个价格变量中。抱歉,如果某些代码
这是我正在学习的一本教科书。 var ingredients = ["eggs", "milk", "flour", "sugar", "baking soda", "baking powder",
我正在从字符串中提取数字并将其传递给函数。我想给它加 1,然后返回字符串,同时保留前导零。我可以使用 while 循环来完成此操作,但不能使用 for 循环。 for 循环只是跳过零。 var add
编辑:我已经在程序的输出中进行了编辑。 该程序要求估计给定值 mu。用户给出一个值 mu,同时还提供了四个不等于 1 的不同数字(称为 w、x、y、z)。然后,程序尝试使用 de Jaeger 公式找
我正在编写一个算法,该算法对一个整数数组从末尾到开头执行一个大循环,其中包含一个 if 条件。第一次条件为假时,循环可以终止。 因此,对于 for 循环,如果条件为假,它会继续迭代并进行简单的变量更改
现在我已经习惯了在内存非常有限的情况下进行编程,但我没有答案的一个问题是:哪个内存效率更高;- for(;;) 或 while() ?还是它们可以平等互换?如果有的话,还要对效率问题发表评论! 最佳答
这个问题已经有答案了: How do I compare strings in Java? (23 个回答) 已关闭 8 年前。 我正在尝试创建一个小程序,我可以在其中读取该程序的单词。如果单词有 6
这个问题在这里已经有了答案: python : list index out of range error while iteratively popping elements (12 个答案) 关
我正在尝试向用户请求 4 到 10 之间的整数。如果他们回答超出该范围,它将进入循环。当用户第一次正确输入数字时,它不会中断并继续执行 else 语句。如果用户在 else 语句中正确输入数字,它将正
我尝试创建一个带有嵌套 foreach 循环的列表。第一个循环是循环一些数字,第二个循环是循环日期。我想给一个日期写一个数字。所以还有另一个功能来检查它。但结果是数字多次写入日期。 Out 是这样的:
我想要做的事情是使用循环创建一个数组,然后在另一个类中调用该数组,这不会做,也可能永远不会做。解决这个问题最好的方法是什么?我已经寻找了所有解决方案,但它们无法编译。感谢您的帮助。 import ja
我尝试创建一个带有嵌套 foreach 循环的列表。第一个循环是循环一些数字,第二个循环是循环日期。我想给一个日期写一个数字。所以还有另一个功能来检查它。但结果是数字多次写入日期。 Out 是这样的:
我正在模拟一家快餐店三个多小时。这三个小时分为 18 个间隔,每个间隔 600 秒。每个间隔都会输出有关这 600 秒内发生的情况的统计信息。 我原来的结构是这样的: int i; for (i=0;
这个问题已经有答案了: IE8 for...in enumerator (3 个回答) How do I check if an object has a specific property in J
哪个对性能更好?这可能与其他编程语言不一致,所以如果它们不同,或者如果你能用你对特定语言的知识回答我的问题,请解释。 我将使用 c++ 作为示例,但我想知道它在 java、c 或任何其他主流语言中的工
这个问题不太可能帮助任何 future 的访问者;它只与一个小的地理区域、一个特定的时间点或一个非常狭窄的情况有关,这些情况并不普遍适用于互联网的全局受众。为了帮助使这个问题更广泛地适用,visit
我是 C 编程和编写代码的新手,以确定 M 测试用例的质因数分解。如果我一次只扫描一次,该功能本身就可以工作,但是当我尝试执行 M 次时却惨遭失败。 我不知道为什么 scanf() 循环有问题。 in
这个问题已经有答案了: JavaScript by reference vs. by value [duplicate] (4 个回答) 已关闭 3 年前。 我在使用 TSlint 时遇到问题,并且理
我尝试在下面的代码中添加 foreach 或 for 循环,以便为 Charts.js 创建多个数据集。这将允许我在此折线图上创建多条线。 我有一个 PHP 对象,我可以对其进行编码以稍后填充变量,但
我是一名优秀的程序员,十分优秀!