c++ - 井字游戏 - 如何在无效输入后不打印结果

Question

现在，当我尝试确定有效输入以再次玩游戏时，它会在显示无效输入后立即再次显示游戏结果，然后要求用户再次输入“y”或“n”。我上传了一张照片给你看。我一辈子都弄不明白。

这是图片: http://imgur.com/SRsMo4P

// GAME OVER
// ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
      while (bGameOver)
      {
            // Display game board - PRINT
            for (int i = 0; i<ROW; ++i)
            {
                cout << " " << board[i][0] << " | " << board[i][1] << " | " << board[i][2] << endl;
                if (i==0 || i==1)
                {
                    cout << " - + - + -" << endl;
                }
            }

            // Player wins - OUTPUT
            if(bWinGame)
            {
                cout << endl;
                cout << " Player "<< playerTurn << " wins! HOORAH! " << endl << endl;
                cout << " Written by: Karolina Sabat - CPSC 1103 - Section: S11" << endl << endl;
            }

            // Play again - OUTPUT & USER INPUT
            //~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
            // VARIABLES
            char again;         // Play again = "Y" or "N"
            cout << endl;
            cout << " Want to play again? ( Y / N )" << endl << endl;
            cout << " "; cin >> again; cout << endl;

            // Play again - if YES        
            if (again == 'y' || again == 'Y')
            {
                bGameOver=false;        // Reset game state
                bWinGame=true;          // Reset assumption

                board[0][0] = '*';      // Rest game board - Array
                board[0][1] = '*';
                board[0][2] = '*';
                board[1][0] = '*';
                board[1][1] = '*';
                board[1][2] = '*';
                board[2][0] = '*';
                board[2][1] = '*';
                board[2][2] = '*';
            }

            // Play again - if NO
            else if (again == 'n' || again == 'N')
            {
                cout << " Awe oh well, thanks for playing. " << endl << endl;
                cout << " Written by: Karolina Sabat - CPSC 1103 - Section: S11" << endl << endl;
                break;
            }

            else
            {
                cout << " INVALID ENTRY: Please input \"Y\" or \"N\" " << endl << endl;
            }
      }

      // Game play continue
      if (!bGameOver)
      {
          // Switch player turn
          if (playerTurn == 1)
          {
              playerTurn = 2;
          }

          else
          {
              playerTurn = 1;
          }

      }  

}



cout << " "; return 0;
}

Answer 1

你在这个else语句中没有break:

else
{
    cout << " INVALID ENTRY: Please input \"Y\" or \"N\" " << endl << endl;
}

代码将继续运行而不会中断，从而导致奇怪的行为。试试这个:

else
{
    cout << " INVALID ENTRY: Please input \"Y\" or \"N\" " << endl << endl;
    break;
}