php - 发布到自己的页面而不是将信息提交到文本文档

Question

我正在为我的 11 年级作业创建一个网站，我们打算发布到一个单独的页面以“订阅时事通讯”并将姓名和电子邮件发送到文本文档中，但我决定接受它更进一步并将其发布到它自己的页面。但是，除非另有说明，否则即使它为“TRUE”，它也不会设置“$ok = TRUE”。当按下提交按钮时，它总是会说“发生错误。您尚未订阅。”

我已将所有 if 语句放在函数中，就好像我没有那样它会显示所有可能的错误代码，因为默认情况下输入字段为空。

这是我的代码:

  <div class="form">
    <form action="" method="post">
        <p>Name: <input type="text" name="name" size="20"></p>

        <p>Email: <input type="text" name="email" size="20"></p>

        <p>Confirm email: <input type="text" name="email2" size="20"></p>

        <input type="submit" name="submit" value="Submit">
    </form>
</div>

<?php

    //Converts data into string
    $name = $_POST['name'];
    $email = $_POST['email'];
    $email2 = $_POST['email2'];
    $ok = TRUE; 

    function fp() {
        if($fp = fopen('nameemail.txt', 'a+')) {
            $ok = TRUE;
            print '<p>fp true</p>';
        }else{
            $ok = FALSE;
            print '<p>fp false</p>';
        };
    }

    function emptyname() {
        if (empty($_POST['name'])){
            print'<font color="red"><p>You did not enter your name</p></font>';
            $ok = FALSE;
        };
    }

    function emptyemail() {
        if (empty($_POST['email'])){
            print'<font color="red"><p>You did not enter an email</p></font>'; 
            $ok = FALSE;
        };
    }

    function emptyemail2() {
        if (empty($_POST['email2'])){
            print'<font color="red"><p>You did not enter a confirm email</p></font>'; 
            $ok = FALSE;
        };
    }

    function emailemail2() {
        if ($_POST['email'] != $_POST['email2']){
            print'<font color="red"><p>Your emails did not match</p></font>';  
            $ok = FALSE;
        };
    }

    function ifok() {
        if($ok == TRUE) {
            fwrite($fp, "{$_POST['name']} - {$_POST['email']}\r\n");
            fclose($fp);
            print "<p><strong>You have been sucessfully subscribed</strong></p>";
            print "<p>Name: $name</p>";
            print "<p>Email: $email</p>";
        }elseif($ok == FALSE){
            print '<p>An error occurred. You have not been subscribed.</p>';
        };
    }

    function okfalse() {
        if($ok == FALSE){
            '<p>Ok is false</p>'; 
        }else{
            '<p>Ok is true</p>';
        };
    }

    if(isset($_POST['submit'])){
        $name = $_POST['name'];
        $email = $_POST['email'];
        $email2 = $_POST['email2'];
        $ok = TRUE;
        fp();
        emptyname();
        emptyemail();
        emptyemail2();
        ifok();
        okfalse();
    }   
?> 

Answer 1

您可以完成所有这一切，而无需尝试使功能正常工作的复杂性。它可以用函数来完成，但你需要在函数内添加全局变量或状态变量，即函数示例($ok)等。此外，使用此类函数的布局比需要的更复杂，发布的布局将不断无论是否填写了所有字段，都调用 isok() 函数。要执行您正在寻找的操作，您可以将代码更改为以下内容:

<?php
if(isset($_POST['submit'])){
    $filename='nameemail.txt';
if (file_exists($filename)) {
    $ok = TRUE;
}else{
    $ok = FALSE;
}
if (empty($_POST['name'])){
    print'<font color="red"><p>You did not enter your name</p></font>';
    $ok = FALSE;
}
if (empty($_POST['email'])){
    print'<font color="red"><p>You did not enter an email</p></font>'; 
    $ok = FALSE;
}
if (empty($_POST['email2'])){
    print'<font color="red"><p>You did not enter a confirm email</p></font>'; 
    $ok = FALSE;
}
if ($_POST['email'] != $_POST['email2']){
    print'<font color="red"><p>Your emails did not match</p></font>';  
    $ok = FALSE;
}
    $name = $_POST['name'];
    $email = $_POST['email'];
    $email2 = $_POST['email2'];

if($ok == TRUE) {
$filename='./nameemail.txt';
$fp = fopen($filename, 'a+');
fwrite($fp, "{$_POST['name']} - {$_POST['email']}\r\n");
fclose($fp);

print "<p><strong>You have been sucessfully subscribed</strong></p>";
print "<p>Name: $name</p>";
print "<p>Email: $email</p>";

}elseif($ok == FALSE){
print '<p>An error occurred. You have not been subscribed.</p>';
} 
}
?>

<div class="form">
<form action="" method="post">
<p>Name: <input type="text" name="name" size="20"></p>
<p>Email: <input type="text" name="email" size="20"></p>
<p>Confirm email: <input type="text" name="email2" size="20"></p>
<input type="submit" name="submit" value="Submit">
</form>
</div>

我选择向您展示此方法，因为您提到如果您没有将请求添加到函数中就会显示错误，这是因为您需要将很多包装在 if(isset($_POST['submit '])) 命令以确保在按下提交按钮之前不会运行代码。

希望这对您有所帮助。