Javascript 检查记录集中的最大/最小/平均数

Question

function lab09unknownLoopCountPart2() {

//Constants
var ONE_HUNDRED = 100;
var ZERO = 0;

//Variables
var employeeHourlyWage;
var hourlyMaximum = ZERO;
var hourlyMinimum = ZERO;
var totalHourlyWage = ZERO;
var records;
var counter = ZERO;
var average;

records = openEmployeePayrollRecords();

while (records.readNextRecord()) {
   employeeHourlyWage  = records.getEmployeeHourlyWage();
   totalHourlyWage += employeeHourlyWage;
   counter++;
   average = totalHourlyWage / counter;

   if (employeeHourlyWage < ONE_HUNDRED) {
       hourlyMaximum = employeeHourlyWage;
   }
   if (employeeHourlyWage < ONE_HUNDRED) {
       hourlyMinimum = employeeHourlyWage;
   }
}
document.write("Average Hourly Wage: " + average + "<br />");
document.write("Maximum Hourly Wage: "  + hourlyMaximum + "<br />");
document.write("Minimum Hourly Wage: " + hourlyMinimum + "<br />");

}

记录集只是 15 - 30 之间的数字。我必须对它们进行排序并找到最大值、最小值和平均值。

我知道我的两个 IF 语句不正确，我想知道如何不使用 Math.min 和 Math.max 来检查这一点。

谢谢。

Answer 1

   var hourlyMinimum = -1;
   var hourlyMaximum = -1;

   if (hourlyMaximum === -1 || employeeHourlyWage > hourlyMaximum ) {
       hourlyMaximum = employeeHourlyWage;
   }
   if (hourlyMinimum === -1 || employeeHourlyWage < hourlyMinimum ) {
       hourlyMinimum = employeeHourlyWage;
   }

假设工资不能为负。