c++ - 关于指针和什么是/不是指针的问题

Question

关于最终指向指针的指针的问题(我怀疑)。请阅读注释代码中提出的问题:

void doodah(char* a);

int main() {

    char d[] = "message"; // one way of assigning a string.
    // char* d = "message"; // another way of assigning a string, but REM'ed out for now.
    cout << d << endl; // d appears not to be a pointer because cout outputs "message", and not an address. Why is this?
    doodah(d); // a function call.
}

void doodah(char* a) {

    cout << a << endl; // this outputs "message" - but why?! What does 'a' mean in this context?
    // cout << *a << endl; // this outputs "m" - but why?! REM'ed out for now.
}

我很困惑!请帮忙。

Answer 1

cout 知道如何在给定 char * 时输出字符串。它不会尝试打印指针值本身。