php - 制作像 mega.nz 这样的侧边栏菜单

Question

我想在 php 中制作一个侧边栏菜单，就像网站 mega.nz 一样

我试过这段代码:

function foldersList($folderName = NULL) {

    $return = '';

    $globFolder = ($folderName != NULL ? $folderName : './server/'.$_SESSION['username']) . "/*";


    foreach (glob($globFolder, GLOB_ONLYDIR) as $subFolder) {

        $baseFolder = basename($subFolder) . '';
        // okay let me see
        // call function to check subfolders - don't forget write `/`
        $subFolders = foldersList($subFolder);

        $return .= '<li><a><i class="fa fa-desktop"></i>' . $baseFolder . '<span class="fa fa-chevron-down"></span></a>';
        $return .= '<ul class="nav child_menu">';

        // if subfolder exist add to return variable
        $return .= $subFolders != '' ? $subFolders : '';


        $return .= '</ul>';
        $return .= '</li>';
    }

    return $return;
}

但问题是文件夹无法识别文件夹内是否有一个文件夹或文件列表。我想，如果文件夹里面有文件列表，转到另一个链接如果是文件夹，多一个文件夹，做下拉菜单，显示这个文件夹。

Answer 1

要跳过空文件夹或只有文件的文件夹，请将函数更改为:

function foldersList($folderName = NULL) {

$return = '';

$globFolder = ($folderName != NULL ? $folderName : './server/'.$_SESSION['username']) . "/*";

$folders = glob($globFolder, GLOB_ONLYDIR);

if(!empty($folders)) {
    foreach ($folders as $subFolder) {

        $baseFolder = basename($subFolder) . '';
        // okay let me see
        // call function to check subfolders - don't forget write `/`
        $subFolders = foldersList($subFolder);

        $return .= '<li><a><i class="fa fa-desktop"></i>' . $baseFolder . '<span class="fa fa-chevron-down"></span></a>';
        $return .= '<ul class="nav child_menu">';

        // if subfolder exist add to return variable
        $return .= $subFolders != '' ? $subFolders : '';


        $return .= '</ul>';
        $return .= '</li>';
    }
}

return $return;}