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c++ - 使用虚拟纯函数访问字段的段错误

转载 作者:行者123 更新时间:2023-11-28 02:35:18 26 4
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我读了很多关于纯虚拟调用的错误,但我没有弄清楚我的代码有什么问题:

我使用多态性编写了国际象棋游戏。

这里是一些代码:

Piece.hpp(所有游戏 block 的父级)

class Piece
{
private:
char _player;
virtual int isMoveLegalForSpecificPiece(int positionRow, int positionCol, int targetRow,
int targetCol, Piece *board[8][8]) = 0;
public:
~Piece()
{
}
Piece(char player);
virtual int isMoveLegal(int positionRow, int positionCol, int targetRow, int targetCol,
Piece *board[8][8]);
char getPlayer();
virtual char getSign() const = 0;
virtual std::string getUnicodeSymbol() const = 0;
};

Rook.hpp(例如)

#include "Piece.hpp"

class Rook : public virtual Piece {
private:
std::string _unicode = "265C";
virtual int isMoveLegalForSpecificPiece(int positionRow, int positionCol, int targetRow,
int targetCol, Piece *board[8][8]);
public:
Rook(char player) : Piece(player){}
~Rook() {}
virtual std::string getUnicodeSymbol() const;
char getSign() const;
};

和 Rook.cpp

#include "Rook.hpp"
char Rook::getSign() const {return 'r';}
int Rook::isMoveLegalForSpecificPiece(int positionRow, int positionCol, int targetRow,
int targetCol, Piece *board[8][8]) {
if (positionRow == targetRow) {
int rightOrLeft = (targetCol - positionCol > 0) ? 1 : -1;
for (int i = positionCol + rightOrLeft; i != targetCol; i += rightOrLeft) {
if (board[positionRow][i] != 0) {return 0; }
}
return 1;
}
else if (positionCol == targetCol) {
int upOrDown = (targetRow - positionRow > 0) ? 1 : -1;
for (int i = positionRow + upOrDown; i != targetRow; i += upOrDown) {
if (board[i][positionCol] != 0) {return 0;}
}
return 1;
}
return 0;
}
std::string Rook::getUnicodeSymbol() const {return _unicode;}

棋盘::棋盘()

Board::Board()  {
for (int i = 0; i < 8; i++) {
for (int j = 0; j < 8; j++) {
board[i][j] = 0;
}
}
for (int i = 0; i < 8; i++) {
board[1][i] = new Pawn('w');
board[6][i] = new Pawn('b');
}
board[7][0] = new Rook('b');
board[0][0] = new Rook('w');
board[7][1] = new Knight('b');
board[0][1] = new Knight('w');
board[7][2] = new Bishop('b');
board[0][2] = new Bishop('w');
board[7][3] = new King('b');
board[0][3] = new King('w');
board[7][4] = new Queen('b');
board[0][4] = new Queen('w');
board[7][5] = new Bishop('b');
board[0][5] = new Bishop('w');
board[7][6] = new Knight('b');
board[0][6] = new Knight('w');
board[7][7] = new Rook('b');
board[0][7] = new Rook('w');
}

板::打印

void Board::print() {
printRowLetters();
for (int i = 7; i >= 0; i--){
cout << (char) ('1' + i) << " ";
for (int j = 7; j >= 0; j--) {
string isColor = "0";
string pieceUnicode = " ";
if (board[i][j]) {
isColor = (board[i][j]->getPlayer() == 'w') ? "37" : "30";
pieceUnicode = board[i][j]->getUnicodeSymbol();
}
//some more code..
}
}
}

我被困在那条线上:

pieceUnicode = board[i][j]->getUnicodeSymbol();

我得到:

pure virtual method called

我没有在构造函数或析构函数中调用函数

在上面的~Piece()析构函数中加上virtual关键字后,这个问题就解决了。但是现在在同一条线上我得到了

Signal: SIGSEGV (Segmentation fault)

有什么想法吗?

这里有更多信息:

我在 chess.cpp 的 main 中声明棋盘:

Board boardGame;

然后我像这样发送到 void playGame(Board boardGame):

playGame(boardGame);

在里面我发送到 void getNextMove(Board board, string whitePlayer, string blackPlayer) 像这样:

getNextMove(boardGame, whitePlayer, blackPlayer);

然后我正在使用:

boardGame.print();

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