Python 3 获取子元素(lxml)

Question

我在 html 中使用 lxml:

from lxml import html
import requests

我如何检查一个元素的任何子元素是否有 class = "nearby"我的代码(本质上):

url = "www.example.com"
Page = requests.get(url)
Tree = html.fromstring(Page.content)
resultList = Tree.xpath('//p[@class="result-info"]')
i=len(resultList)-1 #to go though the list backwards
while i>0:
    if (resultList[i].HasChildWithClass("nearby")):
        print('This result has a child with the class "nearby"')

如何替换“HasChildWithClass()”以使其真正起作用？

这是一个示例树:

...
    <p class="result-info">
        <span class="result-meta">
            <span class="nearby">
                ... #this SHOULD print something
            </span>
        </span>
    </p>
    <p class="result-info">
        <span class="result-meta">
            <span class="FAR-AWAY">
                ... # this should NOT print anything
            </span>
        </span>
    </p>
...

Answer 1

我试图理解您为什么使用 lxml 来查找元素。然而 BeautifulSoup 和 re 可能是更好的选择。

lxml = """
    <p class="result-info">
        <span class="result-meta">
            <span class="nearby">
                ... #this SHOULD print something
            </span>
        </span>
    </p>
    <p class="result-info">
        <span class="result-meta">
            <span class="FAR-AWAY">
                ... # this should NOT print anything
            </span>
        </span>
    </p>
    """

但我做了你想要的。

from lxml import html

Tree = html.fromstring(lxml)
resultList = Tree.xpath('//p[@class="result-info"]')
i = len(resultList) - 1 #to go though the list backwards
for result in resultList:
    for e in result.iter():
        if e.attrib.get("class") == "nearby":
            print(e.text)

尝试使用bs4

from bs4 import BeautifulSoup


soup = BeautifulSoup(lxml,"lxml")
result = soup.find_all("span", class_="nearby")
print(result[0].text)