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javascript - 水平平移 D3.js

转载 作者:行者123 更新时间:2023-11-28 02:19:30 24 4
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我是 D3 的新手,实际上我正在尝试条形图的水平平移选项。我尝试过以下example水平平移工作完美,但我可以看到某些问题。因为我想限制对图表中特定范围内存在的数据的平移(不想水平平移到无穷大),请帮助我解决这个问题。网上有可用的工作示例吗?谢谢。

JS代码:

    var data = [
{"date":"2011-12-31","num":5},
{"date":"2012-01-05","num":10},
{"date":"2012-01-10","num":22},
{"date":"2012-01-15","num":72},
{"date":"2012-01-20","num":87},
{"date":"2012-01-25","num":90}
];


function draw(){

var location = "#post"
var month_names = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec'];
var graph_width = 500;
var graph_height = 200;

var values = _.pluck(data, 'num');
var max_val = d3.max(values);
var v_scale = graph_height / max_val;
var data_counts = data.length;
var bar_width = graph_width / data_counts;
var minDate = new Date(data[0]["date"]);
var maxDate = new Date(data[data.length - 1]["date"]);

var y = d3.scale.linear()
.domain([0, max_val])
.range([graph_height, 0]);

console.log(minDate);
var x = d3.time.scale().domain([minDate, maxDate]).range([0, graph_width]);


var chart = d3.select(location).append("svg")
.attr("class", "chart")
.attr("width", graph_width + 20)
.attr("height", graph_height + 20).
call(d3.behavior.zoom().x(x).scaleExtent([1, 8]).on("zoom", zoom));

var lines = chart.selectAll("line");

var lines_y = lines
.data(x.ticks(5))
.enter().append("line")
.attr("x1", x)
.attr("x2", x)
.attr("y1", function(d) {
return graph_height - 20 - d;})
.attr("y2", graph_height)
.style("stroke", "#ccc");

var lines_x = lines
.data(y.ticks(10))
.enter().append("line")
.attr("x1", 0)
.attr("x2", graph_width)
.attr("y1", y)
.attr("y2", y)
.style("stroke", "#ccc");

xAxis = d3.svg.axis().scale(x);
yAxis = d3.svg.axis().scale(y).orient("left");

chart.append("svg:g")
.attr("class", "xaxis")
.attr("transform", "translate(0,200)")
.call(xAxis);

chart.append("svg:g")
.attr("class", "yaxis")
.attr("transform", "translate(25,0)")
.call(yAxis);

var rect = chart.selectAll("rect")
.data(data).enter()
.append("rect")
.attr("x", function(d, i) {return x(new Date(d["date"])) + 20;})
.attr("y", function(d, i) {return graph_height - (d["num"] * v_scale);})
.attr("width", x(new Date(data[1]["date"])))
.attr("height", function(d, i) {return d["num"] * v_scale;});

function zoom() {
chart.select(".xaxis").call(xAxis);
chart.select(".yaxis").call(yAxis);
chart.selectAll(".chart rect").attr("transform", "translate(" + d3.event.translate[0] + ",0)scale(" + d3.event.scale + ", 1)");
}

}
draw();

最佳答案

这是一个适合任何需要它的人的通用解决方案。通过查看范围而不是 X 刻度的域,这也适用于日期/时间轴。

var zoom = d3.behavior.zoom()
.scaleExtent([1,Infinity])
.on("zoom", function () {
var t = zoom.translate(),
max = d3.max(x.range()),
tx = Math.max( Math.min(0, t[0]), width - max * zoom.scale() );

zoom.translate([ tx, t[1] ]);

draw();
});

关于javascript - 水平平移 D3.js,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15877519/

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