C++父类(super class)和子类

Question

现在它不打印 Bridge 类和子类 RailwayBridge 的所有变量，它只打印出 2 个变量，当我在 Bridge 的 const print 中输入第三个变量名称时，它什么也没有打印出来!修改后的代码在这里:

#include <iostream>
#include <conio.h>
#include <string>

using namespace std;

class Bridge
{
protected:
    int height;
    long payload;
    string name;

public:
    Bridge();
    Bridge(int, long, string);
    ~Bridge() {
        cout << "Message from the \"Bridge\" - destroyed!" << endl;
    }

    int GetHeight() const {
        return height;
    }

    void SetHeight(int _height) {
        height = _height;
    }

    long GetPayload() const {
        return payload;
    }

    void SetPayload(long);

    void SetName(string _name) {
        name = _name;
    }

    std::string GetName() const {
        return name;
    }

    void Print() const;
  };


class RailwayBridge : public Bridge
{
private:
    unsigned int SL;

public:
    RailwayBridge():Bridge(), SL(0) {}
    RailwayBridge(int, long, std::string, unsigned int);

    virtual ~RailwayBridge() {
        cout << endl << "Message from the \"RailwayBridge\" - destroyed!" << endl;
    }

    unsigned int GetSL() const {
        return SL;
    }

    virtual void Print() const;
 };



 Bridge::Bridge() : height(0), payload(0), name("0")
 {
 }

 Bridge::Bridge(int Pheight, long Ppayload, std::string Pname) : height(Pheight){
payload = Ppayload;
 }
 inline void Bridge::SetPayload(long _payload){
payload = _payload;
 }

 inline void Bridge::Print() const {
cout << "Height = " << height << ", Payload = " << payload << ", Name = " << name << endl;
 }


 RailwayBridge::RailwayBridge(int Pheight, long Ppayload, std::string Pname, unsigned int PSL) : Bridge(Pheight, Ppayload, Pname)
 {
 SL = PSL;
 }

 inline void RailwayBridge::Print() const {
 Bridge::Print();
 cout << ", SL = " << SL;
 }



 int main(void)
 {
  const int N = 3;

RailwayBridge *RWB1 = new RailwayBridge(12, 200, "RVans T", 0);
Bridge        *RWB2 = new RailwayBridge(2,30, "Vansu Tilts", 3);

Bridge *Locations[N] = {
    new Bridge(1,2, " akmens tilts "),
    new RailwayBridge(3, 4, "Rail", 5),
    new RailwayBridge(6, 7, "Rails", 8)
};

//clrscr();

cout << "lokaciju masivs: " << endl;
for(int i=0; i<N; i++) {
    cout << (i+1) << ". ";
    Locations[i]->Print();
    cout << endl;
}

cout << endl << "Bridge lokacijas: " << endl;

RWB1->Print();
cout << endl << "Height = " << RWB1->GetHeight() << ".";
cout << endl << "SL = " << RWB1->GetSL() << "." << endl << endl;

for(int k=0; k<N; k++) {
    delete Locations[k];
}
delete RWB1;
delete RWB2;

while (kbhit())
    getch();

getch();


 return 0;

 }

Answer 1

在 RailwayBridge 的构造函数定义中，您忽略了将参数(我猜是桥梁的名称)传递给 Bridge 的构造函数。

您应该如下更改它。

RailwayBridge::RailwayBridge(int Pheight, long Ppayload, string s, unsigned int PSL) : Bridge(Pheight, Ppayload, s) {
SL = PSL;