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C++ 错误 : no match for 'operator>>' in 'input >> Group1->Entrepreneur::Item' |

转载 作者:行者123 更新时间:2023-11-28 02:09:07 24 4
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我遇到了这个错误,并且已经搜索了 4-6 个小时来尝试找到解决方案,但是在我的特定情况下我的搜索都没有产生任何结果,所以这是我的 main.cpp。

#include <iostream>
#include <string>
#include "Entrepreneur.h"
#include <fstream>

using namespace std;

bool operator >(const Entrepreneur & Group1,const Entrepreneur & Group2)
{
if((Group1.Points > Group2.Points || Group1.Points == Group2.Points) && Group1.Profit > Group2.Profit )
{
return true;
}
else
{
return false;
};
};

ostream &operator<<( ostream &output,const Entrepreneur &Group1)
{
output <<"\nItem : " << Group1.Item << "\nNr : " << Group1.Nr << "\nDonation : R" << Group1.Donation << "\nStart up amount : R" << Group1.StartUpAmt << "\nExpenses : R" << Group1.Expenses <<"\nPoints : " << Group1.Points << "\nSold : " << Group1.Sold << endl;;
return output;
};

istream &operator>>( istream &input,const Entrepreneur & Group1)
{
cout << "Enter Items to be sold,Donation amount,number of members & startup amount. Seperated by a space." << endl;

input >> Group1.Item >> Group1.Donation >> Group1.Nr >> Group1.StartUpAmt;
return input;
};

int main()
{


return 0;
};

这是我的头文件。

#ifndef ENTREPRENEUR_H_INCLUDED
#define ENTREPRENEUR_H_INCLUDED
#include <iostream>
#include <string>

using namespace std;

class Entrepreneur{
private:
string Item;
int Nr;
double Donation;
double StartUpAmt;
double Expenses;
double Income;
double Profit;
int Points;
bool Sold;
public:
Entrepreneur(){
Item = "Not Decided";
Nr = 1;
Donation = 0;
StartUpAmt = 0;
Expenses = 0;
Income = 0;
Profit = 0;
Points = 0;
Sold = 0;
};
void CreatGroup(string iItem,int iNr,double iDonation,double iStartUpAmt){
Item = iItem;
Nr = iNr;
Donation = iDonation;
StartUpAmt = iStartUpAmt;
};
void DisplayGroup(){
cout << "\nItem : " << Item << "\nNr : " << Nr << "\nDonation : R" << Donation << "\nStart up amount : R" << StartUpAmt << "\nExpenses : R" << Expenses << "\nIncome : R" << Income << "\nProfit : R" << Profit << "\nPoints : " << Points << "\nSold : " << Sold << endl;
};
void set_info(double iExpenses,double iIncome,bool iSold){
Expenses = iExpenses;
Income = iIncome;
Sold = iSold;
};
void calc_profit(double iDonation,double iStartUpAmt,double iExpenses,double iIncome){
Donation = iDonation;
StartUpAmt = iStartUpAmt;
Expenses = iExpenses;
Income = iIncome;

Profit = Income + (StartUpAmt + Donation) - Expenses;
};
void update_points(){
Points = 0;

if(Nr < 3)
{
Points ++;
}
else
{
Points + 2;
}
if(Donation == 0)
{
Points ++;
}
if(Sold == 1)
{
Points ++;
}
};
void Display(){
cout << "Congratulations to all groups that partook in the challenge !" << endl;
};

friend bool operator >(const Entrepreneur & Group1,const Entrepreneur & Group2);
friend ostream &operator<<( ostream &output,const Entrepreneur & Group1);
friend istream &operator>>( istream &input,const Entrepreneur & Group1);


};

#endif // ENTREPRENEUR_H_INCLUDED

所以错误来自重载运算符的友元成员>>在 Entrepreneur.h 的企业家类中

friend istream &operator>>( istream  &input,const Entrepreneur & Group1);

在 main.cpp 中:

istream &operator>>( istream  &input,const Entrepreneur & Group1)
{
cout << "Enter Items to be sold,Donation amount,number of members & startup amount. Seperated by a space." << endl;

input >> Group1.Item >> Group1.Donation >> Group1.Nr >> Group1.StartUpAmt;
return input;
};

我在谷歌上通常 10 分钟就在这里碰壁了,我会修复它,但是这个让我变得更好。 PS当我开始测试时,这个程序还没有完成。提前致谢。

最佳答案

您正在尝试读入一个const 对象

istream &operator>>(istream  &input, const Entrepreneur & Group1)

这就是为什么你的

input >> Group1.Item >> Group1.Donation >> Group1.Nr >> Group1.StartUpAmt;

不编译。去掉参数声明中的 const

一个不相关的问题

Points + 2;

这是空操作声明。

关于C++ 错误 : no match for 'operator>>' in 'input >> Group1->Entrepreneur::Item' |,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36407380/

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