javascript - 如何将变量从 JSON 传递到原始 Javascript？

Question

这个问题已经有答案了:

How do I return the response from an asynchronous call? (42 个回答)

已关闭 10 年前。

我使用下面的代码成功向 lastFM 发送 getJson 请求。此代码位于 JavaScript 脚本内。我可以从 getJson 函数获取结果并将其用作该函数外部的变量，即在调用 javaScript 中的 this 中吗？

function getArtistInfo(lastFmArtist) {

    var urlArtist = 'http://ws.audioscrobbler.com/2.0/?callback=?',
        params = {
            method:  "artist.getInfo",
            artist: lastFmArtist,
            format:  "json",
            api_key: "xxxxxxxxxx"
        };

    $.getJSON(urlArtist, params, function(data) {

        var myartist = data.artist.bio.summary;

    });
}

alert(myartist);

Answer 1

您可以使用回调

function isFunction(object) {
  return (typeof object == 'function');
}

function getArtistInfo(lastFmArtist, callback) {

  var urlArtist = 'http://ws.audioscrobbler.com/2.0/?callback=?',
  var params = {
        method:  "artist.getInfo",
        artist: lastFmArtist,
        format:  "json",
        api_key: "xxxxxxxxxx"
  };

  $.getJSON(urlArtist, params, function(data) {
    var myartist = data.artist.bio.summary;
    if (isFunction(callback))
    {
      callback(myartist);
    }
  });
}

function getArtistInfoComplete(myartist )
{
  alert(myartist);
}

然后调用它

getArtistInfo(lastFmArtist, getArtistInfoComplete);