c++ - 访问类私有(private)成员中的结构成员？

Question

例如:

graph.h

#ifndef GRAPH_H
#define GRAPH_H

#include <iostream>
#include <string>

using namespace std;

class graph
{
private:
    struct node
    {
        string name;
        int currentValue;
        struct node *next;
    };
    node* head;
public:
    graph();
    ~graph();

    graph(string* newName, int* givenValue);
}

#endif

图形.cpp

#include "graph.h"

graph::graph() {}

graph::~graph() {}

graph::graph(string* newName, int* givenValue)
{
    //This is what I want to achieve
    this->node->name = newName;                    //Compile error
}

main.cpp

#include "graph.h"
#include <iostream>

using namespace std;

int main()
{
    return 0; //Note I have not yet created a graph in main
}

如何访问上述函数的结构节点成员？

这是错误:

graph.cpp: In constructor ‘graph::graph(std::string*, double*)’:
graph.cpp:24:8: error: invalid use of ‘struct graph::node’
this->node->label = newName;

Answer 1

问题与您的私有(private)结构无关。构造函数应该能够访问所有私有(private)成员。

问题是您混淆了结构名称 node 和变量名称 head:

this->node->name = newName; // incorrect

你应该这样写:

 this->head->name = *newName;