c++ - 在简单的 C++ 游戏中遇到问题

Question

我是一名初级程序员，我目前正在学习 C++ 作为我的第一门语言。我一直在尝试制作一个简单的游戏，但它就是不工作。这并不是给我一个错误，而是当我开始时它没有做它应该做的事情。(使用 Code::Blocks)我也知道有很多未使用的类、函数、变量等。

代码:

#include <iostream>
#include <conio.h>
using namespace std;

int main();

//variables
const int X = 0;
const int Y = 10;
const int Z = 0;
int X1 = X;
int Y1 = Y;
int Z1 = Z;
int Input;
int Input2;

int Menu()
{
    cout<<"Please type what you want to do."<<endl;
    cin>>Input;

    return Input;
   //deciding what they want to do.
}

int Calculating()
{
  //Calculating Function(Unused)
}    

class Player
{
public:
    void Movement()
    {
        //the loop that activates when the Input == 1
       while(1)
    {
        cout<<"2 - Move"<<endl;
        do
        {
            cin>>Input2;
        }while(Input2 < 3 && Input2 > 1);

        switch(Input2)
        {
        case 1:
            cout<<"You moved"<<endl;
        }
    }
    }
    void Attack()
    {
       //the loop that activates when the Input == 2
      while(1)
    {
       cout<<"1 - Sword Dance"<<endl;
       do
       {
           cin>>Input2;
       }while(Input2 < 3 && Input2 > 1);

       switch(Input2)
       {
       case 1:
        cout<<"DMG"<<endl;
        break;
       }
    }
    }
};

class Enemy
{
 //Enemy class(Unused)
};   

int main()
{    
    Player Pl;
//if the chosen number was 1 it will make the Player move.
//if the chosen number was 2 it will make the Player attack.
      if(Input == 1)
   {
       Pl.Movement();
   }
   else if(Input == 2)
   {
       Pl.Attack();
   }

    Menu();
 //calling the Menu function
  return 0;
}

Answer 1

在您的 Main 中，您必须将 Menu() 调用为:

int main()
{

    Player Pl;
   Input=Menu();
    //if the chosen number was 1 it will make the Player move.
   //if the chosen number was 2 it will make the Player attack.
   if(Input == 1)
   {
       Pl.Movement();
   }
   else if(Input == 2)
   {
       Pl.Attack();
   }

   Menu();
  //calling the Menu function
  return 0;
}