prototype - JavaScript 原型(prototype)错误

Question

我一直在开发一个 javascript 库。这是代码:

(function (window) {
        var regex = {
            Id : /^[#]\w+$/,
            Class : /^[.]\w+$/,     
            Tag : /^\w+$/,
            validSelector : /^([#]\w+|[.]\w+|\w+)$/
        },  
        tex = function(selector){
            //only some of the functions need to select an element
            //EX:
            // style: tex(selector).style(style);
            //one that would not need a selector is the random number function:
            // tex().random(from,to);
            if (selector){
                if (typeof selector === 'string'){
                    var valid = validSelector.test(selector);
                    if( valid ){
                        if(regex.Id.test(string)){ 
                            this = document.getElementById(selector);
                        }
                        if(regex.Class.test(string)){ 
                            this = document.getElementByClass(selector);
                        }
                        if(regex.Tag.test(string)){ 
                            this = document.getElementByTagName(selector);
                        }
                    }
                }else if(typeof selector === 'object'){
                    this = selector;
                }
                //this = document.querySelector(selector);
                // I could make a selector engine byt I only need basic css selectors.
            }
        },
        tex.prototype = {
            dit : function(){
                this.innerHTML = 'Hi?!?!?!'
            }
        };
        window.tex = tex;
})(window);

在我尝试在网页上使用该库之前，这一切看起来都是不错的代码。当我尝试激活它时，我收到一条错误消息:“错误:意外的标记‘.’”，指的是 tex.prototype 行:

},
tex.prototype = {
    dit : function(){

有人知道我的代码出了什么问题吗？

非常感谢!

Answer 1

也许你应该在声明“tex”之后编写这个原型(prototype)？

    },
    tex.prototype = {
        dit : function(){
            this.innerHTML = 'Hi?!?!?!'
        }
    };

更改为:

};
tex.prototype = {
    dit : function(){
        this.innerHTML = 'Hi?!?!?!'
    }
};