c++ - 将数字打印成文字

Question

我编写了一个程序，将 0-9999 的数字显示为文字。该程序运行正常，但当我输入 11-19 和 415,612,819 之类的数字(基本上所有末尾包含 0-19 的数字)时，我遇到了意外输出。我编写的程序是用 c++ 编写的，我目前是 c++ 的初学者。

//This program converts number into words
#include<iostream>
using namespace std;
main()
{
    int number,unit,ten,hundred,thousand;
    cout<<"Please enter any number between 0-9999: ";
    cin>>number;
    thousand=number/1000;
    number=number%1000;
    hundred=number/100;
    number=number%100;
    ten=number/10;
    number=number%10;
    unit=number;
    if(number>=11 && number <=19)
     {
        if(number==11) cout<<"eleven";
        if(number==12) cout<<"twelve";  
        if(number==13) cout<<"thirteen";
        if(number==14) cout<<"fourteen";
        if(number==15) cout<<"fifteen";
        if(number==16) cout<<"sixteen";
        if(number==17) cout<<"seventeen";
        if(number==18) cout<<"eighteen";
        if(number==19) cout<<"ninteen";
     }
    else
    {    
    if(thousand>=1 && thousand <=9)
    {
        if(thousand==1) cout<<"one thousand";
        if(thousand==2) cout<<"two thousand";
        if(thousand==3) cout<<"three thousand";
        if(thousand==4) cout<<"four thousand";
        if(thousand==5) cout<<"five thousand";
        if(thousand==6) cout<<"six thousand";
        if(thousand==7) cout<<"seven thousand";
        if(thousand==8) cout<<"eight thousand";
        if(thousand==9) cout<<"nine thousand";
    }
    if(hundred>=1 && hundred <=9)
    {
        if(hundred==1) cout<<" one hundred";
        if(hundred==2) cout<<" two hundred";
        if(hundred==3) cout<<" three hundred";
        if(hundred==4) cout<<" four hundred";
        if(hundred==5) cout<<" five hundred";
        if(hundred==6) cout<<" six hundred";
        if(hundred==7) cout<<" seven hundred";
        if(hundred==8) cout<<" eight hundred";
        if(hundred==9) cout<<" nine hundred";
    }
    if(ten>=1 && ten <=9)
    {
        if(ten==1) cout<<" ten";
        if(ten==2) cout<<" twenty";
        if(ten==3) cout<<" thirty";
        if(ten==4) cout<<" fourty";
        if(ten==5) cout<<" fifty";
        if(ten==6) cout<<" sixty";
        if(ten==7) cout<<" seventy";
        if(ten==8) cout<<" eighty";
        if(ten==9) cout<<" ninty";
    }
    if(unit>=1 & unit <=9)
    {
        if(unit==1) cout<<" one";
        if(unit==2) cout<<" two";
        if(unit==3) cout<<" three";
        if(unit==4) cout<<" four";
        if(unit==5) cout<<" five";
        if(unit==6) cout<<" six";
        if(unit==7) cout<<" seven";
        if(unit==8) cout<<" eight";
        if(unit==9) cout<<" nine";
    }
    }
}

输出:-

Please enter any number between 0-9999: 14
 ten four

输出:-

Please enter any number between 0-9999: 114
 one hundred ten four

Answer 1

在这里，您将 number 设置在 0 和 9 之间，到目前为止一切顺利:

number=number%10;

但随后您要检查它是否在 11 和 19 之间。这是不可能的:

if(number>=11 && number <=19)

因此，将跳过整个 block ，取而代之的是最后两个 block 匹配，给你“十四”。第一个 block 可能应该是

if((ten==1) && (number>0))
{
    if(number==1) cout<<"eleven";
    if(number==2) cout<<"twelve";  
    if(number==3) cout<<"thirteen";
    if(number==4) cout<<"fourteen";
    if(number==5) cout<<"fifteen";
    if(number==6) cout<<"sixteen";
    if(number==7) cout<<"seventeen";
    if(number==8) cout<<"eighteen";
    if(number==9) cout<<"ninteen";
 }