C++:打印列表

Question

下面的代码包含我创建的以相反顺序从 1 到 10 编号的表格。 (这是没有中断的代码，后来改变了。)

#include <iostream>

using namespace std;

int main()
{
    switch(1) {
    case 1: cout << "1. blue" << endl;  
    case 2: cout << "2. orange.." << endl;  
    case 3: cout << "3. yellow.." << endl;  
    case 4: cout << "4. green.." << endl;  
    case 5: cout << "5. purple.." << endl;  
    case 6: cout << "6. red.." << endl;  
    case 7: cout << "7. teal.." << endl;  
    case 8: cout << "8. aqua.." << endl;  
    case 9: cout << "9. white.." << endl;  
    case 10: cout << "10. gray.." << endl;  


}

}

我试图让它每次循环运行时，程序将输出对应于下一个较低数字的消息，一个一个地输出。(带中断的代码)

#include <iostream>

using namespace std;

int main() {
for(int i = 10; i>0; --i){
    switch(i) {
    case 1: cout << "1. blue" << endl;  
    break;
    case 2: cout << "2. orange.." << endl;  
    break;
    case 3: cout << "3. yellow.." << endl; 
    break; 
    case 4: cout << "4. green.." << endl; 
    break; 
    case 5: cout << "5. purple.." << endl;  
    break;
    case 6: cout << "6. red.." << endl;  
    break;
    case 7: cout << "7. teal.." << endl;  
    break;
    case 8: cout << "8. aqua.." << endl;
    break;  
    case 9: cout << "9. white.." << endl;  
    break;
    case 10: cout << "10. gray.." << endl; 
    break; 
   }
  }
}

我在向下循环列表并一一列出每个数字/颜色时遇到问题。

在列出每个项目的最后，我希望程序询问用户是否要停止或重新启动循环。

Answer 1

您需要创建一个变量来保存将传递到您的 switch 语句中的变量。你的 switch 语句需要从 10 开始往下走，因为你想先打印 case 10。

#include <iostream>

using namespace std;

int main() {
for(int i = 10; i>0; --i){
    switch(i) {
    case 1: cout << "1. blue" << endl;  
break;
    case 2: cout << "2. orange.." << endl;  
break;
    case 3: cout << "3. yellow.." << endl;  
break;
    case 4: cout << "4. green.." << endl; 
break;
    case 5: cout << "5. purple.." << endl;  
break;
    case 6: cout << "6. red.." << endl;  
break;
    case 7: cout << "7. teal.." << endl;  
break;
    case 8: cout << "8. aqua.." << endl;  
break;
    case 9: cout << "9. white.." << endl;  
break;
    case 10: cout << "10. gray.." << endl;  
break;
   }
  }
}