c++ - 如何将指向结构的指针传递给构造函数？

Question

我想将指向结构的指针(此结构的变量是一个数组，其中的元素具有值 x 和 y)传递给构造函数。接下来我想将这个结构的每个变量的值 x 和 y 分配给类中结构的类似变量值。

class Convex_quadrliteral
{
    protected:
    struct VC {
        float x, y;
    } vertice_coordinate[4];

    public:
    Convex_quadrliteral (VC *pointerVC);
};

Convex_quadrliteral::Convex_quadrliteral (VC *pointerVC) {  
    cout << "\nObject is being created" << endl;

    for (int i = 0; i < 4; i++) //variable initialisation
    {   
        vertice_coordinate[i].x = pointerVC[i].x;
        vertice_coordinate[i].y = pointerVC[i].y;
    }

    //object's properties output
    cout << "Properties: " << endl  
         << "A (" << vertice_coordinate[0].x << ", " << vertice_coordinate[0].y << ")" << endl
         << "B (" << vertice_coordinate[1].x << ", " << vertice_coordinate[1].y << ")" << endl
         << "C (" << vertice_coordinate[2].x << ", " << vertice_coordinate[2].y << ")" << endl
         << "D (" << vertice_coordinate[3].x << ", " << vertice_coordinate[3].y << ")" << endl;
}

int main()
{
    struct vertice_coordinate 
    {
        float x, y;
    };

    vertice_coordinate *pointerVC = new vertice_coordinate[4];

    for (int i = 0; i < 4; i++) {
        pointerVC[i].x = 2;
        pointerVC[i].y = 2;
    }

    Convex_quadrliteral figure_1(pointerVC);

我期望输出:甲(2, 2)乙(2, 2)C(2, 2)D(2, 2)

输出错误:没有声明匹配 'Convex_quadrliteral::Convex_quadrliteral(Convex_quadrliteral::VC*)'C onvex_quadrliteral::Convex_quadrliteral (VC *pointerVC)

Answer 1

您重新定义了 VC 结构，即使结构看起来相同，编译器也会将它们视为两种不同的类型。定义一个结构并在您的类和 main 中使用它。