c++ - 将 unix 时间转换为人类可读的格式

Question

我正在构建自己的 unix 时间到人类可读的转换，但我被卡住了。

我可以很好地提取年份，但事实证明这一天太棘手了。

/*
   Converts a 32-bit number of seconds after 01-01-1970 to a _SYSTEMTIME structure
*/
static _SYSTEMTIME Convert(unsigned long a_UnixTime)
{   
    newtime.wMilliseconds = 0;
    newtime.wYear   = (unsigned long)((float)a_UnixTime / (364.24f * 24.f * 60.f * 60.f));
    newtime.wDay    = (a_UnixTime - (unsigned long)((float)newtime.wYear * 364.24f * 24.f * 60.f * 60.f)); // returns 65177

    return newtime;
}

或者是否有我忽略的内置函数？

提前致谢。

更新:

嗯...Windows Mobile 似乎不支持 strftime、时间或本地时间，所以我还是得自己动手。 :(

Answer 1

你在找 gmtime 吗？

struct tm * gmtime(const time_t *clock);

External declarations, as well as the tm structure definition, are contained in the <time.h> include file.  The tm structure includes at least the following fields:

       int tm_sec;     /* seconds (0 - 60) */
       int tm_min;     /* minutes (0 - 59) */
       int tm_hour;    /* hours (0 - 23) */
       int tm_mday;    /* day of month (1 - 31) */
       int tm_mon;     /* month of year (0 - 11) */
       int tm_year;    /* year - 1900 */
       int tm_wday;    /* day of week (Sunday = 0) */
       int tm_yday;    /* day of year (0 - 365) */
       int tm_isdst;   /* is summer time in effect? */
       char *tm_zone;  /* abbreviation of timezone name */
       long tm_gmtoff; /* offset from UTC in seconds */