c++ - 如何解析要在 C++ 中阻止的文件

Question

我正在寻找一种优雅的方法来将文件解析为 block ，并为每个 block 创建一个新文件，例如:

原始文件:

line 1
line 2
 line 3

line 4
 line 5
   line 6
line 7

结果:

first file:
line 1

second file:
line 2
 line 3

third file:
line 4
 line 5
   line 6

fourth file:
line 7

谢谢

Answer 1

看起来你可以使用这个算法:

Count the number of spaces at the beginning of each line, if it's less than or equal to the number of spaces in the preceding non-empty line, open a new file.

到目前为止你尝试了什么？