c++ - STL map 构建

Question

class Garage {
    string WorkerFirstName;
    string WorkerLastName;
    string WorkerNumber;
public:
    Garage()
    {
        WorkerFirstName = "";
        WorkerLastName = "";
        WorkerNumber = "";
    }

    void SetFirstName(string FirstName) { WorkerFirstName = FirstName;}    
    void SetLastName(string LastName) { WorkerLastName = LastName; }
    void SetNumber(string Number) { WorkerNumber = Number; }

    string GetFirstName() { return WorkerFirstName; }
    string GetLastName() { return WorkerLastName; }
    string GetNumber() { return WorkerNumber; }         
};

class GarageList {
    Garage List[500];                
    int MaxSize;
    int Size;
public:
    GarageList() 
    {
        MaxSize = 500;
    }

    ... //list out functions
};

那是我的设置的精简版。我无法弄清楚如何使用基于姓氏的引用 ID 和包含车库类所有属性的值来制作 map 。我猜像 map< string, Garage List[500] > directory.

Answer 1

你很接近。您正在寻找的是:

map<string, Garage>;

在您的 GarageList 类中使用它，您无需担心条目数量， map 将为您管理。

所以 GarageList 看起来像这样:

class GarageList {
    map<string, Garage> garages_;                
public:
    GarageList() 
    {
    }

    int Size() {
        return garages_.size();
    }

    void AddGarage(const Garage& garage) {
        garages_[garage.GetLastName()] = garage;
    }

    // Return true if found, false otherwise
    bool FindGarage(const string& lastName, Garage& foundGarage) {
        if (garages_.find(lastName) != garages_.end()) {
            foundGarage = garages_[lastName];
            return true;
        }
        return false; // garage not found with lastName
    }
            return 
    ... //list out functions
 };