python - django:从返回结果列表链接到详细信息页面

Question

我正在创建一个页面，该页面在用户搜索后返回包含基本详细信息的电影列表。

搜索后，我希望用户能够点击电影，并获得有关它的更多详细信息。

这是该站点的链接:(请注意，我 2 个月前才开始学习这些东西!哈)http://moniblog.pythonanywhere.com/compare/

数据来自TMDB's api并且初始的“通用”搜索 JSON 响应没有我要在电影的详细信息页面上显示的具体详细信息，但它有一个 ID 将用于特定电影的搜索。

我只使用 views.py 来获取/显示搜索结果，我不确定这是否是正确的方法，或者我是否应该使用模型，但这可能是另一个问题。

表单.py:

from django import forms


class MovieSearch(forms.Form):
    moviename = forms.CharField(label="Search", max_length=250)

views.py:

from django.shortcuts import render, get_object_or_404
from django.conf import settings

from .forms import MovieSearch
import tmdbsimple as tmdb

tmdb.API_KEY = settings.TMDB_API_KEY


def search_movie(request):
    parsed_data = {'results': []}
    if request.method == 'POST':
        form = MovieSearch(request.POST)
        if form.is_valid():
            search = tmdb.Search()
            query = form.cleaned_data['moviename']
            response = search.movie(query=query)
            for movie in response['results']:
                parsed_data['results'].append(
                    {
                        'title': movie['title'],
                        'id': movie['id'],
                        'poster_path': movie['poster_path'],
                        'release_date': movie['release_date'][:-6],
                        'popularity': movie['popularity'],
                        'overview': movie['overview']
                    }
                )
            for i in range(2, 5 + 1):
                response = search.movie(query=query, page=i)
                for movie in response['results']:
                    parsed_data['results'].append(
                        {
                            'title': movie['title'],
                            'id': movie['id'],
                            'poster_path': movie['poster_path'],
                            'release_date': movie['release_date'][:-6],
                            'popularity': movie['popularity'],
                            'overview': movie['overview']
                        }
                    )
            context = {
                "form": form,
                "parsed_data": parsed_data
            }
            return render(request, './moviecompare/movies.html', context)
        else:
            form = MovieSearch()
    else:
        form = MovieSearch()

    return render(request, './moviecompare/compare.html', {"form": form})

和 html:

{% extends 'moviecompare/compare.html' %}

{% block movies_returned %}
<div class="wrap">
<div class="compare-gallery">
{% for key in parsed_data.results|dictsortreversed:'release_date' %}
{% if key.poster_path and key.release_date and key.title and key.overview %}
    <div class="gallery-item">
        <img src="http://image.tmdb.org/t/p/w185/{{ key.poster_path }}">
   <div class="gallery-text">
       <div class="gallery-date"><h5><span><i class="material-icons">date_range</i></span> {{ key.release_date }}</h5></div>
        <div class="gallery-title"><h3><a href="../detail/{{ key.id }}">{{ key.title }}</a></h3></div>  
       <div class="gallery-overview">{{ key.overview|truncatechars:80 }}</div>
       </div>
    </div>
{% endif %}
{% endfor %}
</div>
</div>
{% endblock %}

我已经开始使用 urls.py 来让一些东西起作用，但到目前为止运气不好。

网站的 urls.py:

urlpatterns = [
    url(r'^$', home, name="home"),
    url(r'^blog/', include('blog.urls', namespace='blog')),
    url(r'^compare/', include('moviecompare.urls', namespace='compare')),
    url(r'^movies/', include('moviecompare.urls', namespace='movies')),

和应用程序的 urls.py:

from django.conf.urls import url
from . import views

urlpatterns = [
    url(r'^', views.search_movie, name='compare'),
    url(r'^(?P<movid>[0-9])+$', views.get_movie, name='movies')
]

编辑:在电影详细 View 中添加我的第一次(失败)尝试:

def get_movie(request, movid=None):
    instance = get_object_or_404(request, movid=movid)
    context = {
        'instance': instance
    }
    return render(request, './moviecompare/detail.html', context)

Answer 1

我认为您应该尝试修复这一行中的 urls.py:

url(r'^(?P<movid>[0-9])+$', views.get_movie, name='movies')

像这样移动括号内的“+”:

url(r'^(?P<movid>[0-9]+)$', views.get_movie, name='movies')