javascript - 我如何将从 Firebase 检索的新对象数据转换为 JSON 形式，就像以前一样

Question

我刚刚使用 Yeoman、AngularJS 应用程序设置了 Firebase、angularFire 数据库。我以前常常像这样对我的数据进行硬编码

$scope.data = [
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... },
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... },
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... },
    ...
    ...
    More Data...
    ...
    ...
    { name: 'NAME', description: 'DESCRIPTION', type: 'TYPE', etc: 'ETC', etc: 'ETC', etc: 'ETC'... }
]

当我将上述数据上传到我的 Firebase 数据库时，我必须拥有有效形式的 JSON 数据，因此我将其转换为此形式

[
    { "name": "NAME", "description": "DESCRIPTION", "type": "TYPE", "ect": "ETC","ect": "ETC","ect": "ETC"... },
    { "name": "NAME", "description": "DESCRIPTION", "type": "TYPE", "ect": "ETC","ect": "ETC","ect": "ETC"... },
    { "name": "NAME", "description": "DESCRIPTION", "type": "TYPE", "ect": "ETC","ect": "ETC","ect": "ETC"... },
    ...
    ...
]

这是有效的 JSON 格式。现在，当我 console.log(firebaseRef) 时，我的数据将以下面的形式检索。这正是我在 Google Chrome 控制台中看到的内容。

Object {$bind: function, $add: function, $save: function, $set: function, $transaction: function…}
    0: Object
         description: "DESCRIPTION""
         name: "NAME"
         type: "TYPE""
         etc: "ETC"
         etc: "ETC"
         etc: "ETC"
         ...more data...
         __proto__: Object
    1: Object
         description: "DESCRIPTION""
         name: "NAME"
         type: "TYPE""
         etc: "ETC"
         etc: "ETC"
         etc: "ETC"
         ...more data...
         __proto__: Object
    2: Object
         description: "DESCRIPTION""
         name: "NAME"
         type: "TYPE""
         etc: "ETC"
         etc: "ETC"
         etc: "ETC"
         ...more data...
         __proto__: Object
    ...
    ...
    ...More Data...
    ...
    ...

如何将从 Firebase 检索的新对象数据转换为与之前相同的形式？

这是两者之间主要区别的图片。我收到的 Firebase 数据似乎是一个包含多个对象的对象，而我之前想要/使用的数据是多个对象的数组。

Answer 1

根据这个网址:Object to array - quick conversion

您需要将 firebase 对象分配给一个变量:

$scope.firebaseObj

然后你可以通过以下方式将其填充到 $scope.data 对象中:

$scope.data = [];
 for (var i = 0; i < $scope.firebaseObj.length; i++) {
      $scope.data[i]['name']= $scope.firebaseObj[i].name;
      $scope.data[i]['description']= $scope.firebaseObj[i].description;
      $scope.data[i]['type'] =  $scope.firebaseObj[i].type;
      $scope.data[i]['etc1'] =  $scope.firebaseObj[i].etc1;
      $scope.data[i]['etc12'] =  $scope.firebaseObj[i].etc2;
      .
      .
      . 
 }

只有当 JSON 中的每个元素都具有相同的属性时，这才有效