c++ - 如何在 C++ 中生成的随机数应用程序中的数字之间留出空格？

Question

我需要能够在每个数字之间出现空格。这是我的代码。任何帮助都是极好的!这个应用程序还允许您为 1 - 49 之间的 insta 选择号码生成 6 行 6 个数字，它必须选择两行 6 个数字，1 - 49 用于扭曲，1 行 6 个数字用于标签。

    #include <iostream> 
    #include <iomanip>
    #include <cstdlib>
    using namespace std;

    int main()
    {
    {
cout << "*** LOTTO  MAX  INSTA  PICK ***" << endl;
cout<< " " << endl << endl;
    }

    {
cout << "Your Insta Pick Numbers" << endl;
cout<< " " << endl << endl;
    }
for (int counter = 1; counter <= 24; ++ counter)
{

    cout << setw(1) << (1 + rand() % 49);


    if (counter % 6 == 0)
        cout << endl;
}
{
    cout<< " " << endl << endl;
    cout<< " " << endl << endl;
}
{
cout << "Your Twist Numbers" << endl;
cout<< " " << endl << endl;
    }
for (int counter = 1; counter <= 12; ++ counter)
{

    cout << setw(1) << (1 + rand() % 49) , "  ";


    if (counter % 6 == 0)
        cout << endl;

}
{
    cout<< " " << endl << endl;
    cout<< " " << endl << endl;
}


{
cout << "Your Tag Numbers" << endl;
cout<< " " << endl << endl;
    }
for (int counter = 1; counter <= 6; ++ counter)
{

    cout << setw(1) << (1 + rand() % 12);


    if (counter % 6 == 0)
        cout << endl;

}
{
    cout<< " " << endl << endl;
   cout<< " " << endl << endl;
}
{
cout << "Thank you for playing!! please check ticket a year minus a day               from date of purchase" <<endl;
}
    };

Answer 1

当你这样做的时候，你几乎拥有了它

cout << setw(1) << (1 + rand() % 49) , "  ";

但这并不像您认为的那样。它计算两个表达式，用逗号分隔 - cout << setw(1) << (1 + rand() % 49)和 " " .第一个执行 setw并打印 (1 + rand() % 49) ，第二个只是对自身求值，没有任何效果。请记住 <<是 cout 的输出运算符, 所以你只需要将逗号更改为 << :

cout << setw(1) << (1 + rand() % 49) << "  ";

同样的事情也适用于你打印数字的其他地方。