c++ - 如何摆脱丑陋的记录

Question

class c {
    private:
        int n[10];
    public:
        c();
        ~c();
        int operator()(int i) { return n[i];};
};

class cc {
    private:

    public:
        c *mass;
        cc();
        ~cc();
        c& operator*() const {return *mass;};
};
int somfunc() {
    c *c1 = new c();

    cc * cc1 = new cc();

    (*cc1->mass)(1);



    delete c1;
}

我有一个指向 cc 类的指向 c 类的指针。

有没有办法去掉这样的记录:

(*cc1->mass)(1);

然后这样写:

cc1->mass(1);

不可能吗？

Answer 1

当我看到“c++”和“运算符重载”标签时，我的脑海里响起了警报。

C++ 运算符重载很复杂，一些运算符如“()”或“->”使其变得更加困难。

我建议，在重载运算符之前，创建一个具有相同目的的全局函数或方法，测试它是否有效，然后用运算符替换它。

全局好友函数示例:

class c {
    private:
        int n[10];      

    public:
        c();
        ~c();

        // int operator()(int i) { return n[i]; } 

        // there is a friend global function, that when receives a "c" object,
        // as a parameter, or declares a "c" object, as a local variable,
        // this function, will have access to the "public" members of "c" objects,
        // the "thisref" will be removed, when turned into a method
        friend int c_subscript(c thisref, int i) ;
};

int c_subscript(c* thisref, int i)
{
  return c->n[i];
}

int main()
{
  c* objC() = new c();
  // do something with "objcC"

  int x = c_subscript(objC, 3);
  // do something with "x"

  return 0;
} // int main(...)

局部函数(“方法”)示例:

class c {
    private:
        int n[10];      

    public:
        c();
        ~c();

        // int operator()(int i) { return n[i]; }

        int subscript(int i) ;
};

int c::subscript(int i)
{
  return this.n[i];
}

int main()
{
  c* objC() = new c();
  // do something with "objcC"

  int x = c->subscript(objC, 3);
  // do something with "x"

  return 0;
} // int main(...)

最后使用重载运算符:

class c {
    private:
        int n[10];      

    public:
        c();
        ~c();   

        int subscript(int i) ;

        int operator()(int i) { return this.subscript(i); }
};

int c::subscript(int i)
{
  return this.n[i];
}

int main()
{
  c* objC() = new c();
  // do something with "objcC"

  int x = c->subscript(3);
  // do something with "x"

  int x = c(3);
  // do something with "x"

  return 0;
} // int main(...)

请注意，在最后一个示例中，我为方法保留了唯一标识符。

干杯。