gpt4 book ai didi

php - 请求 .php 时 css 不工作,如 "/example.php/"但显示内容

转载 作者:行者123 更新时间:2023-11-28 00:54:17 25 4
gpt4 key购买 nike

我正在用 php 开发一个脚本,我将每个部分分隔为 .php 文件,以便将它们放入 include() php 函数中。

所以在我分开之后

  1. header.php
  2. 页脚.php
  3. 等..

每个文件夹中的 include() 都很好,例如,如果您想在浏览器中查看文件:

http://localhost/yourfile.php很好!

http://localhost/yourfile.php/坏的!

当你添加 (/) 时,它会显示 yourfile.php 的内容但没有 css!

我尝试添加具有值(value)的.htaccess

<IfModule mod_rewrite.c>
RewriteEngine On
RewriteRule ^index\.php$ - [L]
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . /snapchat/index.php [L]
</IfModule>

和 header 值

<html lang="en" class="no-js">
<head>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
<link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.4.1/css/all.css" integrity="sha384-5sAR7xN1Nv6T6+dT2mhtzEpVJvfS3NScPQTrOxhwjIuvcA67KV2R5Jz6kr4abQsz" crossorigin="anonymous">
<link rel="stylesheet" type="text/css" href="assest/css/styles.css">
<!-- javascript files -->
<script src="https://code.jquery.com/jquery-3.3.1.min.js" integrity="sha384-tsQFqpEReu7ZLhBV2VZlAu7zcOV+rXbYlF2cqB8txI/8aZajjp4Bqd+V6D5IgvKT" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js" integrity="sha384-ZMP7rVo3mIykV+2+9J3UJ46jBk0WLaUAdn689aCwoqbBJiSnjAK/l8WvCWPIPm49" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js" integrity="sha384-ChfqqxuZUCnJSK3+MXmPNIyE6ZbWh2IMqE241rYiqJxyMiZ6OW/JmZQ5stwEULTy" crossorigin="anonymous"></script>
<script type="text/javascript" src="assest/js/main.js"></script>
<!-- end imported files -->
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<title>title</title>
</head>
<body>

最佳答案

那是因为你的 css 链接是相对的,例如 assest/css/styles.css ,所以浏览器尝试从 http://localhost/yourfile.php/assest/css 下载样式/styles.css

如果将 css 的传递更改为此 /assest/css/styles.css,浏览器将从 http://localhost/assest/css/styles.css< 加载样式(考虑路径开头的 /)

关于php - 请求 .php 时 css 不工作,如 "/example.php/"但显示内容,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53033163/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com