c++ - 在 C++ 中尝试/抛出/捕获 : what's wrong with my code?

Question

请问你能检查一下这段代码吗？ try/catch/throw 有什么问题？

#include<iostream>
using namespace std;

int get_input();

int main() {

    int number, base_in, base_out;
    bool pass = 1;

    while(pass) {

        double number, base_in, base_out;

        try {

            cout << "What's your number? ";
            number = get_input();

            pass = 0;

        }
        catch(problem_type()) {
            cout << "Please, write inputs should be integer" << endl;
        }

    }

    return 0;
}


int get_input(bool target = 1) {

    double n;
    cin >> n;

    if(n != (int)n) throw problem_type();

    if(target) {
        if(n<1) throw problem_type();
    }

    return (int)n;

}

Answer 1

您按类型捕获。喜欢

catch(const problem_type&){ }

也就是说，如果 problem_type 是类型。我在任何地方都看不到定义......