c++ - rand() 函数 C++

Question

我需要生成 4 个随机数，每个随机数在 [-45 +45] 度之间。如果 rand%2 = 0 那么我想要结果(生成的随机数等于 -angle)。一旦生成了 4 个随机数，就需要扫描这些角度并找到一个锁(角度相交的点)。此外，if 语句中循环中的 -3、-2、-1、... +3 表示锁定发生在 6 度波束宽度内。代码有效。但是可以简化吗？目标也是通过扫描两点的仰角和方位角在两点之间建立锁定。

  #include <iostream>
  #include <conio.h>
  #include <time.h>
  using namespace std;

  class Cscan
  {
    public:
    int gran, lockaz, lockel;

  };

  int main()
  {
     srand (time(NULL));
    int az1, az2, el1, el2, j, k;


    BS1.lockaz = rand() % 46;
    BS1.lockel = rand() % 46;
    BS2.lockaz = rand() % 46;
    BS2.lockel = rand() % 46;

    k = rand() % 2;
    if(k == 0)
            k = -1;
    BS1.lockaz = k*BS1.lockaz;

    k = rand() % 2;
    if(k == 0)
            k = -1;
    BS1.lockel = k*BS1.lockel;

            k = rand() % 2;
    if(k == 0)
            k = -1;
    BS2.lockaz = k*BS2.lockaz;

    k = rand() % 2;
    if(k == 0)
            k = -1;
    BS2.lockel = k*BS2.lockel;

    for(az1=-45; az1<=45; az1=az1+4)
    {
            for(el1=-45; el1<=45; el1=el1+4)
            {
                    for(az2=-45; az2<=45; az2=az2+4)
                    {
                            for(el2=-45; el2<=45; el2=el2+4)
                            {

           if((az1==BS1.lockaz-3||az1==BS1.lockaz-2||az1==BS1.lockaz-1||az1==BS1.lockaz||az1==BS1.lockaz+1||az1==BS1.lockaz+2||az1==BS1.lockaz+3)&&

           (az2==BS2.lockaz-3||az2==BS2.lockaz-2||az2==BS2.lockaz-1||az2==BS2.lockaz||az2==BS2.lockaz+1||az2==BS2.lockaz+2||az2==BS2.lockaz+3)&&

           (el1==BS1.lockel-3||el1==BS1.lockel-2||el1==BS1.lockel-1||el1==BS1.lockel||el1==BS1.lockel+1||el1==BS1.lockel+2||el1==BS1.lockel+3)&&

            (el2==BS2.lockel-3||el2==BS2.lockel-2||el2==BS2.lockel-1||el2==BS2.lockel||el2==BS2.lockel+1||el2==BS2.lockel+2||el2==BS2.lockel+3))
                                    {      
             cout << "locked \n" << BS1.lockaz << " " << BS1.lockel << " " << BS2.lockaz << " " << BS2.lockel <<endl
              < az1 << " " << el1 << " " << az2 << " " << el2 << endl;
                                                    k = 1;
                                            break;
                                    }
                                    if(k==1)
                                            break;
                            }
                            if(k==1)
                                    break;
                    }
                    if(k==1)
                            break;
            }
            if(k==1)
                    break;
    }
    _getch();
  }       

Answer 1

BS1.lockaz = rand() % 91 - 45;
BS1.lockel = rand() % 91 - 45;
BS2.lockaz = rand() % 91 - 45;
BS2.lockel = rand() % 91 - 45;