javascript - Wicket AjaxButton 和 javascript 条件

Question

我是 Wicket 框架的新手，所以我不知道这是否可行。我希望当我点击表单的提交按钮(在Java中是AjaxButton)时弹出javascript确认对话框，但是当我点击“否”时，它总是调用该按钮的onSubmit方法。我做错了什么？

这是我的代码:

AjaxButton submit;
add(submit = new AjaxButton("ajaxSubmitProduct"){
    private static final long serialVersionUID = 1L;

    @Override
    protected void onComponentTag(ComponentTag tag)
    {
        super.onComponentTag(tag);
        tag.put("onclick", "return confirm('Yes or No?');");
    }
    @Override
    protected void onSubmit(AjaxRequestTarget target, Form<?> form) {
        target.add(form);

        Product p = (Product) form.getModelObject();
        DBBroker.save_product(p);
        success("You have sucessfully added a new product.");
    }

    @Override
    protected void onError(AjaxRequestTarget target, Form<?> form)
    {
        target.add(form);
    }

});    

Answer 1

您应该使用 Ajax 前提条件:

https://cwiki.apache.org/confluence/display/WICKET/Getting+user+confirmation