c++ - boost 使用 struct 中包含的 typedef 定义的 native 类型的序列化

Question

我有一个 MyFile.hpp 头文件，其中包含各种类型和枚举。我如何对给定的示例代码进行序列化/反序列化。

//我的文件.hpp

namespace A { 
   namespace B {

      typedef std::string MyString;
      typedef std::map<std::string,std::string> my_type;
      typedef bool result;

      struct MyTimer
      {
         int time;

       private :
         friend class boost::serialization::access;
         template<class Archive>
         void serialize(Archive &ar, const unsigned int version)
         {
            ar & time;
         }
      };

      enum MODE
      {
          Sleep=1,
          HybridSleep,
          Hybernate
      }

   }
}

我需要在相应的 MyFile.cpp 中进行实现，但不知道如何进行。

谢谢，

Answer 1

map 、字符串等可以通过包含相关的 header 来序列化:

#include <boost/serialization/map.hpp>
#include <boost/serialization/string.hpp>

枚举 counts as a primitive type:

A type T is Serializable if and only if one of the following is true:

• it is a primitive type.

  By primitive type we mean a C++ built-in type and ONLY a C++ built-in type. Arithmetic (including characters), bool, enum are primitive types. Below in serialization traits, we define a "primitive" implementation level in a different way for a different purpose. This can be a source of confusion.

• It is a class type and one of the following has been declared according to the prototypes detailed below:
  • a class member function serialize
  • a global function serialize
• it is a pointer to a Serializable type.
• it is a reference to a Serializable type.
• it is a native C++ Array of Serializable type.

对于更棘手的情况，有 BOOST_STRONG_TYPEDEF(参见 documentation "Serialization Wrappers")