javascript - 如何处理 OVER_QUERY_LIMIT

Question

这个问题已经有答案了:

OVER_QUERY_LIMIT in Google Maps API v3: How do I pause/delay in Javascript to slow it down? (6 个回答)

How do I Geocode 20 addresses without receiving an OVER_QUERY_LIMIT response? (7 个回答)

已关闭 8 年前。

我正在使用谷歌地图绘制存储在数据库中的各个位置之间的路径。

fiddle

在通过 15 个地理点(任何超过 10 个)时，我的状态为 OVER_QUERY_LIMIT。

我知道，当我们每秒经过超过 10 个地理点时，我们需要给出几毫秒的时间间隙。

我的问题是如何做到这一点..在哪里添加 sleep() 或 setTimeout() 或任何其他时间延迟代码

我已经尝试了SO提供的所有可能性，但失败了。因为他们只是说在请求之间给出一些时间间隔，但如何做到这一点？

代码片段:

    var markers = [
                        {
                            "title": 'abc',
                            "lat": '17.5061925',
                            "lng": '78.5049901',
                            "description": '1'
                        },                  


                        {
                            "title": 'abc',
                            "lat": '17.50165',
                            "lng": '78.5139204',
                            "description": '2'
                        },
                        .
                        .
                        .
                        .
                        .
                        {
                            "title": 'abc',
                            "lat": '17.4166067',
                            "lng": '78.4853992',
                            "description": '15'
                        }

         ];


    var map;

    var mapOptions = {
        center: new google.maps.LatLng(markers[0].lat, markers[0].lng),
        zoom: 15    ,
        mapTypeId: google.maps.MapTypeId.ROADMAP
    };

    var path = new google.maps.MVCArray();
    var service = new google.maps.DirectionsService();

    var infoWindow = new google.maps.InfoWindow();
    var map = new google.maps.Map(document.getElementById("map"), mapOptions);

    var poly = new google.maps.Polyline({
        map: map,
        strokeColor: '#000000'
    });

    var lat_lng = new Array();

    for (var i = 0; i <= markers.length-1; i++)
    {
           var src = new google.maps.LatLng(markers[i].lat, markers[i].lng);
           var des = new google.maps.LatLng(markers[i+1].lat, markers[i+1].lng);

            poly.setPath(path);
            service.route({
                origin: src,
                destination: des,
                travelMode: google.maps.DirectionsTravelMode.DRIVING
            }, 
           function (result, status)
           {
                if (status == google.maps.DirectionsStatus.OK)
                {
  for (var i = 0, len = result.routes[0].overview_path.length;
       i < len; i++) 
                    {
                        path.push(result.routes[0].overview_path[i]);

                    }
                 } 
                 else{

                     if (status == google.maps.GeocoderStatus.OVER_QUERY_LIMIT)
                     {      
                          document.getElementById('status').innerHTML +="request failed:"+status+"<br>";
                     }                                    

            } 
         });

    }
  });

结果图(OVER_QUERY_LIMIT):

Answer 1

Google 推荐:

Lowering usage, by optimizing applications to use the web services more efficiently.

Increasing usage limits, when possible, by purchasing additional allowance for your Google Maps API for Work license.

还有HERE有一些解决方法似乎适合您的需要

if status == "OVER_QUERY_LIMIT": 
    time.sleep(2)

这是用 Phyton 编写的，但您可以将其用作 Pseudocode ，它很容易阅读:

url = "MAPS_API_WEBSERVICE_URL"
attempts = 0
success = False

while success != True and attempts < 3:
  raw_result = urllib.urlopen(url).read()
  attempts += 1
  # The GetStatus function parses the answer and returns the status code
  # This function is out of the scope of this example (you can use a SDK).
  status = GetStatus(raw_result)
  if status == "OVER_QUERY_LIMIT":
    time.sleep(2)
    # retry
    continue
  success = True

if attempts == 3:
  # send an alert as this means that the daily limit has been reached
  print "Daily limit has been reached"

在您的 javascript 代码中，只需设置超时即可:

if (status == google.maps.GeocoderStatus.OVER_QUERY_LIMIT)
{      
    setTimeout(3000);
}      

检查working fiddle