c++ - 从随机单词中删除重复的字符

Question

我正在创建一个类来删除随机单词中的重复字符。例如，如果输入是“aabbccddeeff”，它应该输出“abcdef”。但是我的输出在“abcdef”之后包含奇怪的字符。 main.cpp文件已经存在，作为创建类的要求。请看下面的代码:

主.ccp

#include <iostream>
#include "repeatdeletion.h"

using namespace std;

int main()
{
    char* noRepeats;
    int length;
    string s;

    cout<<"Enter a random word with repeating characters: ";
    cin>>s;

    RepeatDeletion d;
    length=s.length();
    noRepeats=d.deleteRepeats(s, length);

    cout<<"Your word without any repeating characters: ";
    for (int k=0; k<length; k++){
        cout<<noRepeats[k];
    }
    cout<<endl;

    delete [] noRepeats;
    noRepeats=NULL;

    return 0;
}

重复删除.h

#ifndef REPEATDELETION_H
#define REPEATDELETION_H
#include <iostream>

using namespace std;

class RepeatDeletion
{
    char* c;
    char arr[128]={};
    bool repeated;
    bool isRepeated(char);
public:
    RepeatDeletion();
    ~RepeatDeletion();
    char* deleteRepeats(string, int);
};

#endif // REPEATDELETION_H

重复删除.cpp

#include "repeatdeletion.h"

RepeatDeletion::RepeatDeletion()
{
    repeated=false;  
}

RepeatDeletion::~RepeatDeletion()
{
    delete [] c;
    c=NULL;
}

bool RepeatDeletion::isRepeated(char c){
    bool repeated=false;
    if (arr[c]>=1){
        repeated=true;
        arr[c]++;
    }else{        
        arr[c]++;
    }
    return repeated;
}

char* RepeatDeletion::deleteRepeats(string str, int len){
    c=new char[len];
    int j=0;
    for (int i=0; i<len; i++){
        if (isRepeated(str[i])==false){
            c[j]=str[i];
            j++;
        }
    }
    return c;
}

Answer 1

您的返回字符数组不是空终止的。string的长度函数不包含\0。

你有两个选择

1. 在返回的字符数组末尾添加null，std::cout 直接char数组(而不是逐个字符)

2. 输出 char 数组的最终长度，并将其用作范围以逐个字符地打印它