c++ - C++ 文件中逗号后的股票值

Question

我正在尝试检测并忽略同一行到股票值(value)的逗号。

我试了getline的3个参数，没用。我也试过迭代器，一样。

我的文本文件包含以下值:

Bob Jackson,25,Sick
Eric Smith,99,Deceased
Alice Vanderlend,16,Healthy

在下面的代码中，我在我的失败尝试中添加了注释...

string str,fn, ln, age, sta;
    ifstream input("text.txt");


    while (getline(input, str)) 
    {   
        /*for ( string::iterator it=str.begin(); it!=str.end(); ++it)
        {
            if ((*it) == ','){continue;};
        }*/

        //string vir;
        istringstream iss(str);

        //if(!(getline(input, vir, ','))){break;}

        iss >> fn >> ln >> age >> sta;

        cout 
        << "First Name: " << fn 
        << "\nLast Name: " << ln 
        << "\nAge: " << age 
        << "\nStatus: " << sta << endl  << endl;

    }

我期望得到的输出是

First Name: Bob
Last Name: Jackson
Age: 25
Status: Sick
...

相反，我得到:

First Name: Bob
Last Name: Jackson,25,Sick
Age:
Status:
...

如何忽略逗号来存储下一个值？

Answer 1

如下声明一个虚拟变量:

char comma;

并读出多余的逗号:

iss >> fn >> ln >> comma>> age >> comma >> sta;

代替

iss >> fn >> ln >> age >> sta;