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c++ - 为什么我在控制台做双缓冲时会出现随机符号?

转载 作者:行者123 更新时间:2023-11-28 00:20:04 25 4
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我正在尝试在控制台中使用双缓冲。我已经编写了这段代码,它可以编译,但是在创建的控制台中,最下面的几行充满了随机字符。更改CHAR_INFO cur[Width*Height];进入CHAR_INFO cur[Width*Height+200]; 有帮助,但我不明白为什么 Width*Height 的内存不够用。

#include <windows.h>
#include <ctime>

#define xMax 80
#define yMax 25
#define fPS 250
#define Delay 60

class dbconsole
{
private:
int width, height, FPS, delay;
HANDLE h0, h1;
CHAR_INFO *chiBuffer;
bool curBuffer;
int drawingTimer;
public:
dbconsole(int Width, int Height, int fps)
{
CHAR_INFO cur[Width*Height];
width = Width;
height = Height;
FPS = fps;
preparebuffer(h0);
preparebuffer(h1);
chiBuffer = cur;
curBuffer = 0;
drawingTimer = clock();
}
void preparebuffer(HANDLE &h)
{
CONSOLE_CURSOR_INFO cursor;
cursor.bVisible = false;
cursor.dwSize = 1;
h = CreateConsoleScreenBuffer(
GENERIC_READ | GENERIC_WRITE,
FILE_SHARE_READ | FILE_SHARE_WRITE,
NULL,
CONSOLE_TEXTMODE_BUFFER,
NULL);
SetConsoleCursorInfo(h, &cursor);
}
void putpixel(int x, int y, CHAR_INFO input)
{
chiBuffer[x+width*y]=input;
}
void depict()
{
SMALL_RECT srctWriteRect;
srctWriteRect.Top = 0;
srctWriteRect.Left = 0;
srctWriteRect.Bottom = yMax-1;
srctWriteRect.Right = xMax-1;
if ((clock()-drawingTimer)*FPS>CLOCKS_PER_SEC)
{
if (curBuffer)
{
WriteConsoleOutput(h0, chiBuffer, {xMax,yMax}, {0,0}, &srctWriteRect);
SetConsoleActiveScreenBuffer(h0);
}
else
{
WriteConsoleOutput(h1, chiBuffer, {xMax,yMax}, {0,0}, &srctWriteRect);
SetConsoleActiveScreenBuffer(h1);
}
curBuffer=!curBuffer;
drawingTimer = clock();
}
}
};

int main(void)
{
dbconsole myConsole = dbconsole(xMax,yMax,fPS);
SetConsoleTitle("Use arrow keys to control character");
long long movetimer = clock();
int x = 0, y = 0;
while (true)
{
for (int i = 0; i < xMax; i++) for (int j = 0; j < yMax; j++) myConsole.putpixel(i,j, {' ',16});
if ((clock()-movetimer)*Delay>CLOCKS_PER_SEC)
{
if (GetAsyncKeyState(VK_RIGHT))
{
movetimer = clock();
if (x < xMax-1) x++;
}
if (GetAsyncKeyState(VK_LEFT))
{
movetimer = clock();
if (x > 0) x--;
}
if (GetAsyncKeyState(VK_DOWN))
{
movetimer = clock();
if (y < yMax-1) y++;
}
if (GetAsyncKeyState(VK_UP))
{
movetimer = clock();
if (y > 0) y--;
}
if (GetAsyncKeyState(VK_ESCAPE)) return 0;
}
myConsole.putpixel(x,y,{1,15|16});
myConsole.depict();
}
}

我认为问题是由于chiBuffer对应的一些内存没有为它保留,但我不明白为什么。那么,问题是什么?

最佳答案

这里:

dbconsole(int Width, int Height, int fps)
{
CHAR_INFO cur[Width*Height];
....
chiBuffer = cur;

cur是一个局部变量,一旦离开构造函数,它就不存在了。此时,chiBuffer 不再是一个有效的指针,任何对它的使用都会导致未定义的行为。

一个简单的解决方案是使 chiBuffer 成为 std::vector:

// also: #include <vector> at the top
std::vector<CHAR_INFO> chiBuffer;

并像这样在构造函数中初始化它:

dbconsole(int Width, int Height, int fps)
: chiBuffer(Width * Height)
{
// cur no longer necessary.

唯一需要的额外改变是

//                     v----------v--- here
WriteConsoleOutput(h0, &chiBuffer[0], {xMax,yMax}, {0,0}, &srctWriteRect);

从 vector 中提取 C 函数 WriteConsoleOutput 可以理解的指针。这是可行的,因为 std::vector 保证它在内存中连续存储其元素(如数组)。

关于c++ - 为什么我在控制台做双缓冲时会出现随机符号?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27965064/

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