td标签内的javascript onclick

Question

我想提交<form>与 <table>在里面。如何提交<form>使用默认操作？与<select>标签我可以使用 onchange 提交表单JavaScript 函数。我以为onclick="this.form.submit"里面<td>标签可以解决，但 firebug 指示错误:TypeError: this.form is undefined

出了什么问题？

<div class="report">
  <form method="post" name="status_students">
    <table width="100%" border="0" cellspacing="0" cellpadding="0">
      <tr>
        <td class="tdreport">Active</td>
        <td class="tdreport">Unstable</td>
        <td class="tdreport">Inactive</td>
      </tr>
      <tr>
        <td class="active" name="students_actives" value="actives" onclick="this.form.submit()">
          <?php
          if ($this->siteCenterSelected == "All") {
          echo count($this->usersStatus['verde']);
          } else {
          echo count($this->usersStatusSiteCenter['verde']);
          }
          ?>
        </td>
        <td class="unstable"><?php
          if ($this->siteCenterSelected == "All") {
          echo count($this->usersStatus['amarelo']);
          } else {
          echo count($this->usersStatusSiteCenter['amarelo']);
          }
          ?>
        </td>
        <td class="inactive"><?php
          if ($this->siteCenterSelected == "All") {
          echo count($this->usersStatus['vermelho']);
          } else {
          echo count($this->usersStatusSiteCenter['vermelho']);
          }
          ?>
        </td>
      </tr>
    </table>
  </form>
</div>

Answer 1

您在 onclick 函数中引用的

this 对象是单击的 td，而不是整个文档。您可能想改用它:

onclick="document.forms[0].submit()"

但事实上，您最好通过 ID 来引用表单。