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javascript - 将谷歌地图API圈导出到kml

转载 作者：行者123 更新时间：2023-11-28 00:13:12 26 4
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我正在尝试将圆导出为 kml 格式并放入文本区域中进行下载。可以用 google map api 来实现吗？我是否需要登录 Google 并在其中创建 map ，或者我可以使用 JavaScript 来完成此操作。

 <!DOCTYPE html>
    <html>
      <head>
        <title>Simple Map</title>
        <meta name="viewport" content="initial-scale=1.0, user-scalable=no">
        <meta charset="utf-8">
        <style>
          html, body, #map-canvas {
            height: 700px;
            width: 1400px;
            margin: 0px;
            padding: 0px
          }
        </style>
        <script src="https://maps.googleapis.com/maps/api/js?v=3.exp&signed_in=true"></script>
        <script>
            var map;
            function initialize() {
              var mapOptions = {
                zoom: 8,
                center: new google.maps.LatLng(42.364294, -71.061730)
              };
            map = new google.maps.Map(document.getElementById('map-canvas'),
          mapOptions);
            }

            google.maps.event.addDomListener(window, 'load', initialize);

        </script>
      </head>
      <body>
        <div id="map-canvas"></div>
            <form onsubmit="download(this['name'].value, this['text'].value)">
                <input type="text" name="name" value="test.kml">
                <textarea name="text" value= ""></textarea>
                <input type="submit" value="Download">
            </form>
            <form onsubmit="plotPoint(this['latitude'].value, this['longitude'].value, this['radius'].value); return false">
                Latitude: <input type="text" name ="latitude">
                Longitude:<input type="text" name ="longitude">
                Radius: <input type="text" name ="radius">
                <input type="submit" value="Plot Point">
            </form>
            <script>

            function download(filename, text) {
              var pom = document.createElement('a');
              pom.setAttribute('href', 'data:text/plain;charset=utf-8,' + encodeURIComponent(text));
              pom.setAttribute('download', filename);

              pom.style.display = 'none';
              document.body.appendChild(pom);

              pom.click();

              document.body.removeChild(pom);
            }

            function plotPoint(latitude, longitude, radius){
                var myLatlng = new google.maps.LatLng(latitude, longitude );
                var marker = new google.maps.Marker({
                    position: myLatlng,
                    map: map,
                });

                console.log(radius);
                var circleOptions = {
                  strokeColor: '#FF0000',
                  strokeOpacity: 0.8,
                  strokeWeight: 2,
                  fillColor: '#FF0000',
                  fillOpacity: 0.35,
                  map: map,
                  center: myLatlng,
                  radius: parseFloat(radius)
                };
                // Add the circle for this city to the map.
                circle = new google.maps.Circle(circleOptions);
            }
        </script>
      </body>
    </html>

最佳答案

KML 中没有“圈子”。您需要生成具有正确半径的圆形多边形。我在此页面上实现了一个版本:

example

如果您单击“生成 KML”，您将获得此 KML:

<?xml version="1.0" encoding="UTF-8" ?>
<kml xmlns="http://www.opengis.net/kml/2.2">
  <Document>
    <Placemark>
      <name><![CDATA[]]></name>
      <description><![CDATA[]]></description>
      <Polygon>
        <extrude>1</extrude>
        <altitudeMode>relativeToGround</altitudeMode>
        <outerBoundaryIs>
          <LinearRing>
            <coordinates>
              75.97323066160926,20.34462694382967,0
              75.96496457627045,20.5023906507352,0
              75.94024592717449,20.658635006900816,0
              75.89931276842476,20.81185529376479,0
              75.8425593087164,20.96057591620589,0
              75.77053211489097,21.10336461333105,0
              75.68392484819908,21.23884625193071,0
              75.58357158396333,21.36571606976336,0
              75.47043877897697,21.48275224112917,0
              75.34561596399672,21.588827643719412,0
              75.21030525096592,21.68292071342043,0
              75.06580975601942,21.764125282534497,0
              74.91352104976282,21.83165930667011,0
              74.75490575568685,21.884872396256995,0
              74.59149142578141,21.92325208015319,0
              74.42485182937483,21.94642874102231,0
              74.256591796875,21.954179174950532,0
              74.08833176437517,21.94642874102231,0
              73.92169216796859,21.92325208015319,0
              73.75827783806315,21.884872396256995,0
              73.59966254398718,21.83165930667011,0
              73.44737383773058,21.764125282534497,0
              73.30287834278408,21.68292071342043,0
              73.16756762975328,21.588827643719412,0
              73.04274481477303,21.48275224112917,0
              72.92961200978667,21.36571606976336,0
              72.82925874555092,21.23884625193071,0
              72.74265147885903,21.10336461333105,0
              72.6706242850336,20.96057591620589,0
              72.61387082532524,20.81185529376479,0
              72.57293766657551,20.658635006900816,0
              72.54821901747955,20.5023906507352,0
              72.53995293214074,20.34462694382967,0
              72.54821901747955,20.18686323692414,0
              72.57293766657551,20.030618880758524,0
              72.61387082532524,19.87739859389455,0
              72.6706242850336,19.72867797145345,0
              72.74265147885903,19.58588927432829,0
              72.82925874555092,19.45040763572863,0
              72.92961200978667,19.323537817895982,0
              73.04274481477302,19.20650164653017,0
              73.16756762975328,19.10042624393993,0
              73.30287834278408,19.00633317423891,0
              73.44737383773058,18.925128605124844,0
              73.59966254398718,18.85759458098923,0
              73.75827783806315,18.804381491402346,0
              73.92169216796859,18.76600180750615,0
              74.08833176437517,18.74282514663703,0
              74.256591796875,18.73507471270881,0
              74.42485182937483,18.74282514663703,0
              74.59149142578141,18.76600180750615,0
              74.75490575568685,18.804381491402346,0
              74.91352104976282,18.85759458098923,0
              75.06580975601942,18.925128605124844,0
              75.21030525096592,19.00633317423891,0
              75.34561596399672,19.10042624393993,0
              75.47043877897697,19.20650164653017,0
              75.58357158396333,19.323537817895982,0
              75.68392484819908,19.45040763572863,0
              75.77053211489097,19.58588927432829,0
              75.8425593087164,19.72867797145345,0
              75.89931276842476,19.87739859389455,0
              75.94024592717449,20.030618880758524,0
              75.96496457627045,20.18686323692414,0
              75.97323066160926,20.34462694382967,0
            </coordinates>
          </LinearRing>
        </outerBoundaryIs>
      </Polygon>
    </Placemark>
  </Document>
</kml>

That KML displayed on a Google Maps Javascript API v3 map

生成圆的代码是:

if (result.overlays[i].type == "circle"){
  //its a polygon, approximate a circle by a circular 64 sided polygon.
  xw.writeStartElement('outerBoundaryIs');
  xw.writeStartElement('LinearRing');
  xw.writeStartElement( "coordinates" );
  var d2r = Math.PI / 180;   // degrees to radians 
  var r2d = 180 / Math.PI;   // radians to degrees 
  var earthsradius = 6378137; // 6378137 is the radius of the earth in meters
  var dir = 1; // clockwise

  var points = 64; 

  // find the raidus in lat/lon 
  var rlat = (result.overlays[i].radius / earthsradius) * r2d; 
  var rlng = rlat / Math.cos(result.overlays[i].center.lat * d2r); 

  var extp = new Array(); 
  if (dir==1)   {
    var start=0;
    var end=points+1
  } // one extra here makes sure we connect the line
  else {
    var start=points+1;
    var end=0
  }
    for (var j=start; (dir==1 ? j < end : j > end); j=j+dir) { 
      var theta = Math.PI * (j / (points/2)); 
      ey = result.overlays[i].center.lng + (rlng * Math.cos(theta)); // center a + radius x * cos(theta) 
      ex = result.overlays[i].center.lat + (rlat * Math.sin(theta)); // center b + radius y * sin(theta) 
      xw.writeString( ey + "," + ex + ",0" );
  } 
  xw.writeEndElement();
  xw.writeEndElement();
  xw.writeEndElement();

关于javascript - 将谷歌地图API圈导出到kml，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30690279/

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