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c++ - 修改 unique_ptr 的目标并用它初始化一个 const unique_ptr

转载 作者:行者123 更新时间:2023-11-28 00:10:09 27 4
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假设 class OwnerMember 成员,它还必须有一个指向它的 const 所有者的 const 指针。该指针在 Owner 的构造函数中提供给 member,该构造函数接受指向构成 member 的指针作为参数。

考虑 Owner 的构造函数:

using namespace std;

class Owner;

class Member {
friend class Owner;
private:
// this object needs to know its owner for whatever reason
void setOwnership(const Owner* o){
if(owner != nullptr){
throw logic_error("Already owned.");
}
owner = o;
}
const Owner* owner;
};

class Owner {
public:

Owner(Member* m)
: member(move(m))
{
m->setOwnership(this);
}

// need to define copy ctor, move ctor, copy assignment, move assignment, destructor
// because we own member

protected:
const Member* const member;
};

现在我想让 unique_ptr 为我处理 member 的所有权,所以我尝试

class Owner {
public:

// ATTEMPT 1
Owner(unique_ptr<Member> m)
: member(move(m))
{
member->setOwnership(this); // this doesn't work because member points to a const
}

// ATTEMPT 2
Owner(unique_ptr<Member> m){
m->setOwnership(this);
member = move(m); // this doesn't work because member is const
}

protected:
const unique_ptr<const Member> member;
};

Owner 的构造函数的两次尝试都无法编译。我该怎么做呢?原则上似乎没有我不能这样做的理由。

我是否必须为了方便使用 unique_ptr 而牺牲其中一个 const

最佳答案

委托(delegate)构造函数来救援:

class Owner {
public:
Owner(std::unique_ptr<Member> m) : Owner(m, m.get()) {}

private:
Owner(unique_ptr<Member>& m, Member* ptr) : member(std::move(m)){
ptr->setOwnership(this);
}

protected:
const std::unique_ptr<const Member> member;
};

关于c++ - 修改 unique_ptr 的目标并用它初始化一个 const unique_ptr,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33570230/

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